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garri49 [273]
2 years ago
9

How do you find the slop and y intercept of a graph

Mathematics
1 answer:
NemiM [27]2 years ago
7 0
Y=mx+b is the formula you use to find the answer
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Each pot of coffee served 10 people. How many tablespoons are needed if you want enough coffee to serve 80 people?
podryga [215]

Answer:

8 pots

Step-by-step explanation:

7 0
2 years ago
In which cell structure does MOST of the process of cellular respiration take place?A.nucleusB.vacuoleC.cell wallD.mitochondrion
Zielflug [23.3K]

Mitochondria, therefore D

5 0
3 years ago
Hey can someone plz help me with this??? *cute eyes*
Leto [7]

Answer:

A. 5

B. -5, 5

C. 5, 5

Step-by-step explanation:

A. |-6+(-1)| = 5

B. -6-(-1)=-6+1=-5

-1-(-6)=-1+6=5

C. |-6-(-1)|=|-6+1|=5

|-1-(-6)|=|-1+6|=5

5 0
3 years ago
 The distance between city A and B is 600 km. The first train left A and headed towards B at the speed of 60 km/hour. The secon
hoa [83]
\bf \begin{array}{ccccllll}
&distance&rate(km/hr)&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
A&d&60&t\\
B&600-d&v&t+3
\end{array}

\bf \textit{meaning}\implies 
\begin{cases}
d=(60)(t)
\\ \quad \\
600-d=(v)(t+3)\\
------------\\
d=\boxed{60t}\qquad thus
\\ \quad \\
600-\boxed{60t}=v(t+3)\leftarrow \textit{solve for "t"}
\end{cases}

keep in mind, that "t" is the time when the train at A station, left towards B station

they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference
8 0
2 years ago
Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor
docker41 [41]

Given:

The table of values is

Number of Students   :  7    14   21    28

Number of Textbooks : 35  70  105  140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

\dfrac{35}{7}=5

\dfrac{70}{14}=5

\dfrac{105}{21}=5

\dfrac{140}{28}=5

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

\dfrac{y}{x}=k

Here, k=5.

\dfrac{y}{x}=5

y=5x

Hence the rate of change is constant that is 5.

8 0
3 years ago
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