Answer:
Q3: x1=2+i, x2=2-i Q4: x1=-3/2+i, x2=-3/2-i
Step-by-step explanation:
( ±
) /
= (
x1= 2+i
x2= 2-i
( ±
) /
= (-6 ±
)/4= (-3 ± i)/2
x1 = -3/2 +i
x2 = -3/2 -i
30 POINTS 7TH GRADE MATH! There are 15 girls in your class this year. That is a 15% increase from last year.
1 answer:
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The two positive numbers satisfying the given requirements are 15.56 and 15.56
For given question,
Let x and y be two positive numbers satisfying the given requirements.
⇒ xy = 242 .............(1)
The sum of given two positive numbers is a minimum.
Let the sum of given two positive numbers is S.
⇒ x + y = S ............(2)
From equation(1),
⇒ y = 242/x
Substitute above value of y in equation (2),
⇒ x + y = S
⇒ S = x + (242 / x)
Now, for above equation we find the derivative of x with respect to x.
⇒ 0 = 1 -
⇒ 242/x² = 1
⇒ x² = 242
⇒ x = ±15.56
Since the numbers are positive, x = 15.56
For x = 15.56
⇒ y = 15.56
Therefore, the two positive numbers satisfying the given requirements are 15.56 and 15.56
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