Find the perimeter of the triangle, round to the nearest tenth

Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre

choli [55]

Answer:

$z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

$\hat p=\frac{46}{115}=0.4$ estimated proportion of people that have traded in their old car

$p_o=0.48$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:

Null hypothesis: $p\geq 0.48$

Alternative hypothesis: $p < 0.48$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.

4 0

4 years ago

Children of mothers who smoked during pregnancy scored nine points lower on intelligence tests at ages three and four than child

eduard

Answer:

All of the options apply.

Step-by-step explanation:

In the example given in the question, it is stated that mothers' smoking during pregnancy can affect childs' IQ and can cause lower scores on test.

All of the given options can be given as evidence for the link between smoking and lower IQ. The diet especially throughout childhood has significant effect on the development of the brain and the prefrontal cortex.

The psychological condition that the child is in, the environment in the house that he/she grows up in affects the IQ and the EQ.

The IQ can be affected by outside factors but it also has a relation with the genes that the child takes from his/her parents.

The socioeconomic status of the mother can affect the environment that the child grows up in, the people he/she interacts with and the opportunities that he/she gets to stimulate the brain in different ways to encourage growth.

I hope this answer helps.

8 0

3 years ago

How to solve this algebraically?

Keith_Richards [23]

Ok so x+4-1 makes x-1 so i belive the answer could be 1/5

7 0

3 years ago

Read 2 more answers

It’s just a graph, but I need the answers.

lana66690 [7]

Answer: