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sergij07 [2.7K]
3 years ago
15

Sole for |p+8| over 2 =5

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

p =2                     p=-18

Step-by-step explanation:

|p+8|

-------------- = 5

2

Multiply each side by 2

|p+8|

-------------*2 = 5*2

2

|p+8|  =10

There is a positive and a negative solution

p+8=10         p+8=-10

Subtract 8 from each side

p+8-8=10-8         p+8-8=-10-8

p =2                     p=-18



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f(x)=|x+2|\\\\g(x)=-x^2\\\\(g\circ f)(x)=-x^2|x+2|=-|x^2|\cdot|x+2|=-|x^2(x+2)|=-|x^3+2x^2|\\\\(g\ \circ\ f)(3)=-|3^3+2(3)^2|=-|27+2(9)|=-|27+18|=-45
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In how many ways can you park 4 different cars at a car park with 5 different parking spaces?
meriva
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3 years ago
David is making a rectangular exercise yard for his turtle, Ralph. The perimeter of the yard is
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yd=

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1 year ago
Which of the following expressions is modeled on the number line?
Anton [14]
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7 0
3 years ago
Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin
jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

<u>GIVEN :-</u>

There are 2 right-angled triangles.

In the triangle on the right side ,

  • Hypotenuse = 26m
  • Base = 10m

In the triangle on the left side ,

  • Base = 18m

<u>TO FIND :-</u>

  • Length of the common perpendicular to both triangles.
  • Length of the hypotenuse of the triangle on the left side.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • Hypotenuse = \sqrt{Base^2 + Perpendicular^2}.
  • Perpendicular = \sqrt{Hypotenuse^2 - Base^2}

<u>SOLUTION :-</u>

In the triangle on the right side ,

Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m

∴ x = 30m

3 0
3 years ago
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