All categories

3 years ago

5. What is the solution to the equation -2.5(x-4)=-3x+4?

Mathematics

2 answers:

Mice21 [21]3 years ago

8 0

Answer: -12

Step-by-step explanation:

-(25/10)*(x-4)-(-3*x+4)=0

(0 - (5/2— • (x - 4))) - (4 - 3x) = 0

-5 • (x-4) - ((4-3x) • 2)/2 = x + 12/2

x+12 /2 • 2 = 0 • 2

-12

lana66690 [7]3 years ago

6 0

Answer:

x = -12

Step-by-step explanation:

-2.5(x-4)=-3x+4

Distribute

-2.5x +10 = -3x +4

Add 3x to each side

-2.5x+10 +3x = -3x+4+3x

.5x +10 = 4

Subtract 10 from each side

.5x+10-10=4-10

.5x = -6

Divide by .5

.5x/.5 = -6/.5

x = -12

You might be interested in

Help plz.. plz plz lmz

Nutka1998 [239]

Answer:

seven hundred and twenty nine

6 0

3 years ago

It took Everly 55 minutes to run a 10-kilometer race last weekend. If you know that 1 kilometer equals 0.621 mile, how many minu

slega [8]

$\bf \cfrac{10km}{55mins}\cdot \cfrac{0.621miles}{1km}\implies \cfrac{62.1miles}{55mins}\approx 1.12909909\approx \boxed{1.13\frac{miles}{mins}}$

5 0

3 years ago

What is the reciprocal of 6/5? <br> A. 1 <br> B. 1 1/5 <br> C. 12/10 <br> D. 5/6

Sergio039 [100]

The reciprocal of 6/5 is D. 5/6

Reciprocal simply means swapping the position of the numbers in the fraction. The numerator becomes the denominator and the denominator becomes the numerator.

We need to get reciprocal of a fraction when division is performed.

For example: 2 ÷ 1/5

2 may be a whole number but in fraction form it is 2/1.

1st fraction = 2/1
2nd fraction = 1/5

In dividing fractions, the 1st step we need to do is to get the reciprocal of the 2nd fraction.

1/5 ⇒ 5/1

Then, we multiply the 1st fraction to the reciprocal of the 2nd fraction.
2/1 * 5/1 = 10

So, 2 ÷ 1/5 = 10

8 0

3 years ago

Read 2 more answers

The following data points are the yearly salaries (in thousands of dollars) of the 4 high school cheerleading

GarryVolchara [31]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]