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cricket20 [7]
3 years ago
6

the graph of g(x) is the graph of f(x)=|x| translated 6 units to the right write the equation of g(x)

Mathematics
1 answer:
anyanavicka [17]3 years ago
8 0

Answer:

f(x)=|x-6|

Step-by-step explanation:

Translation is a shift. Opposite how many units it moved. In with the x because that's side to side. If it was not with the x, it's up and down.

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Find the missing value if <br> f(x) = 2.<br> x=____<br> NEED HELP ASAP!!!
Yuri [45]

Answer:

i think its possibly 4

Step-by-step explanation:

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3 years ago
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joes family has compleated 60% of a road trip. if they have traveld 30 miles, how far is the full road trip?
Tems11 [23]

The full road trip is 50 miles.

Step-by-step explanation:

Given,

Distance traveled by Joe's family = 30 miles

This represents 60% of the total distance to be traveled.

Let,

x be the total distance.

60% of x = 30

\frac{60}{100}*x=30\\0.6x=30

Dividing both sides by 0.6

\frac{0.6x}{0.6}=\frac{30}{0.6}\\x=50\ miles

The full road trip is 50 miles.

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/3375830
  • brainly.com/question/3398261

#LearnwithBrainly

4 0
3 years ago
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
Whats the difference between range and interquartile range?
miv72 [106K]

Answer:

Step-by-step explanation:

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A graphic artist has a picture that is 5 inches by 10 inches. The picture
tangare [24]

Answer:

15 inches

Step-by-step explanation:

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3 years ago
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