Answer:
yea sorry bud i dont know about this one maybe try doing it yourself
Step-by-step explanation:
Hello!
I believe that there are 8 people on the midfielder team
1/4 is the equivalent to 25% and 2 is 25% of 8. When you divide 2 by 0.25, you will get 8 as your answer
I hope this helps!
Answer: 0.05
Step-by-step explanation:
Let M = Event of getting an A in Marketing class.
S = Event of getting an A in Spanish class,
i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45
Required probability = P(neither M nor S)
= P(M'∩S')
= P(M∪S)' [∵P(A'∩B')=P(A∪B)']
=1- P(M∪S) [∵P(A')=1-P(A)]
= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]
= 1- (0.80+0.60-0.45)
= 1- 0.95
= 0.05
hence, the probability that Helen does not get an A in either class= 0.05
Answer:
i did this before the answer is c
For slightly greater clarity, write this expression as
sqrt(6x^8y^9) 6x^8y^9
-------------------- This is equivalent to sqrt[ -------------------- ]
sqrt(5x^2y^4) 5x^2y^4
Reduce the quantity inside the square brackets, obtaining:
6*x^6*y^5
sqrt[ ---------------- ]
5
This simplifies as follows: sqrt[ 6/5 ] * [ x^3 * y^(5/2)
which can be simplified even further if you wish.
