Construct the perpendicular bisector of one side of triangle
Construct the perpendicular bisector of another side
Where they cross is the center of the Circumscribed circle
Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle!
Lets write this out:-
2.4 + 0.8 =______ - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___
So to solve d blanks we will do d following:-
2.4 + 0.8 = 3.2
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___
Now lets solve again:-
3.2 - 0.06 = 3.14
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21=_____+1.78=_____- 5.14=___
Now lets solve again:-
3.14 + 1.21= 4.25
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78=_____- 5.14=___
Now lets solve again:-
4.25 +1.78= 6.03
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14=___
Now lets solve again:-
6.03 - 5.14 = 0.89
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89
So, 2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89
Hope I helped ya!! xD
Answer:
The angle is about 30.27 degrees.
Step-by-step explanation:
Use the trig ratio cosine because you are given the adjacent leg and the hypotenuse.
Plug into a calculator
Rounded to the nearest hundredth the angle is 30.27 degrees.
Answer:
X=10.2
Step-by-step explanation:
