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MArishka [77]
3 years ago
5

A deep sea diver is 28 feet below sea level.the location of the diver is represe nted by the integer -28he swims down and additi

onal 5 feet to explore a reef then he swims up 15 feet to watch a school of fish
Mathematics
1 answer:
Alona [7]3 years ago
6 0
He is at -18 feet because you do -28 - 5 which equals -33 after that you do -33 + 15
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Solve this equation. 5n+7=7(n+1)-2n
9966 [12]
Distribute 7 to both n and 1

7(n + 1) = 7n + 7

5n + 7 = 7n + 7 - 2n

Combine like terms

5n + 7 = 7n - 2n + 7

5n + 7 = 5n + 7

If you want to solve for n, subtract 7 from both sides

5n + 7 (-7) = 5n + 7 (-7)

5n = 5n

then divide 5 from both sides

5n/5 = 5n/5

n = n

Effectively, this equation is <em>unsolvable</em>

hope this helps
3 0
3 years ago
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A new roll of wrapping paper has 6 5/8 yards of paper. Drew used 2 1/6 yards from the roll to wrap a gift. Which equation most c
Sedbober [7]
First you have to make both fractions have the same denominator, so you can multiply each fraction by the others denominator.

5/8
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(5*6)/(8*6)

And

1/6
To
(1*8)/(6*8)

Now it's 6 30/48 - 2 8/48

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Now reduce to

= 4 11/24

So, 4 11/24 is the answer

3 0
3 years ago
Which of the diagrams below represents the statement, "If it is not an apple, then it is not fruit"?
kherson [118]
I'm pretty sure it is figure A
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3 years ago
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HELLLLLLP!!!!! PLEASE!!!!
blagie [28]

Answer: Slope: -1    Y-intercept: -4

Step-by-step explanation:

Slope formula:

m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

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m=\frac{-7}{7\\}

m = -1

When you draw this on the graph, the y-intercept is -4.

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3 years ago
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The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
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