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3 years ago

5

Two stores carry a similar stereo for the same original price of $573 one store offers a 16% discount and the other store sells

the stereo for $458.40 which store gives the bigger percent discount justify your answer

1 answer:

mr Goodwill [35]3 years ago

3 0

The store that sells the stereo at $458.50

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Yo 9th grade algebra 2 just answer the bottom row i did the rest by myself.

lilavasa [31]

Answer:

5. (x-8)(x+2)

10. (x-5)(x-5) OR (x-5)^2

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3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

lidiya [134]

2x^2 - quadratic - monomial
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3 years ago

Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-10, 12) and point (5, 3) rounded

Whitepunk [10]

Answer:

<h3>The answer is 17.5 units</h3>

Step-by-step explanation:

Using the distance formula

<h3> $d = \sqrt{ ({x2 - x1})^{2} + ({y2 - y1})^{2} }$ </h3>

the distance between (-10, 12) and (5, 3) is

<h3> $d = \sqrt{ ({5 + 10})^{2} + ({3 - 12})^{2} }$ </h3><h3> $d = \sqrt{ {15}^{2} + ( { - 9})^{2} }$ </h3><h3> $d = \sqrt{225 + 81}$ </h3><h3> $d = \sqrt{306}$ </h3><h3> $d = 3 \sqrt{34}$ </h3>

d = 17.492855

We have the final answer as

<h3>d = 17.5 units to the nearest tenth</h3>

Hope this helps you

4 0

3 years ago

Read 2 more answers

If x degree and 115 degree are co exterior angles find the vaule of x degree

Lesechka [4]

Answer:

65 degrees

Step-by-step explanation:

An exterior angle form a linear pair with an interior angle.

A linear pair of angles must add up to 180 degrees

180-115 = 65

3 0

3 years ago

A train goes twice as fast downhill as it can go uphill, and 2/3 feet as fast uphill as it can go on level ground. If it goes 12

Yuri [45]

Answer:

0.5hrs

Step-by-step explanation:

Let the speed downhill be $x$ ,

Speed uphill is $0.5x$ . We are told than speed uphill is $\frac{2}{3}$ the speed on flat ground. Therefore the speed on level ground will be $\frac{0.5x}{2/3}=0.75x$ .

From this info, we can obtain the actual speed, $v_g$ on level ground as:

$x=120m/h\\0.75x=v_g\\\\\therefore v_g=\frac{0.75x \times 120m/h}{x}\\v_g=90m/h$

speed, distance and time have the relation $s=d/t$ so to obtain time to cover 45miles:

$t=d/s\\=45/90\\=0.5h$

Hence it takes 0.5hrs to cover 45miles on flat ground.

4 0

3 years ago