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Nataly_w [17]
2 years ago
12

Help guys pls i beg u cannot do the math this so hard someone help ☺️☺️☺️☺️☺️☺️☺️☺️

Mathematics
2 answers:
Molodets [167]2 years ago
8 0
200= 13.5xV+65
200 because that’s what she needs to equal. Then multiple 13.5 by V because you are accounting for how many times she visits and how many points she will get per visit. Then you add 65 because she already has that amount from signing up.
Trava [24]2 years ago
8 0
V >= (200 - 65) / 13.5
V >= 10
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Help pls need help before my daughter pls and thank you ​
WITCHER [35]

Answer:

I would say line d

Step-by-step explanation:

its the line of best fit (has the most points going through it)

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3 years ago
4 inches away from a playground the scale of the map is 1 inch represents 5.25 meters how far apart are the actual pond and play
liubo4ka [24]
5.25 times 4 = 21 meters!

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3 years ago
5c+10=40.................
jeka94

Answer

c=6

Step-by-step explanation:

subtract both sides by ten

c+10-10=40-10

5c=30

divide both sides by 5

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6 0
3 years ago
Read 2 more answers
mrs. warburton weighs her suitcases ready for holiday.It weighs 7.35kg she takes out shoes that weigh 2.6.How heavy is her suitc
kiruha [24]
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6 0
3 years ago
Read 2 more answers
The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
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