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Nataly_w [17]
3 years ago
12

Help guys pls i beg u cannot do the math this so hard someone help ☺️☺️☺️☺️☺️☺️☺️☺️

Mathematics
2 answers:
Molodets [167]3 years ago
8 0
200= 13.5xV+65
200 because that’s what she needs to equal. Then multiple 13.5 by V because you are accounting for how many times she visits and how many points she will get per visit. Then you add 65 because she already has that amount from signing up.
Trava [24]3 years ago
8 0
V >= (200 - 65) / 13.5
V >= 10
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Gemiola [76]
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7 0
3 years ago
If your mom only has half a gallon left will she make it to the nearest gas station 26 miles away
Svetach [21]

Answer:

Depends how much is half a gallon in her car

usally a car has 100+ space for gallons

if she has any less than 50 gallons max

she won’t make it

so she probley will if she has more than 26 gallons of gas at half a tank

7 0
3 years ago
Triangle ABC has vertices A(5, 3) , B(3, 7) , and C(1, 4) . Triangle ABC is dilated, and the vertices of the image are A′(7.5, 4
Oksana_A [137]
Hello,

To find the scale factor, we have to look at what's going on in the problem. 

In point A, we are converting from (5, 3) to (7.5, 4.5).

We can write and solve equation to find the change (scale factor)

5x = 7.5  and 3x = 4.5

If you solve either equation, you will find the scale factor is 1.5.

Good luck,
MrEQ
8 0
4 years ago
Read 2 more answers
Are ABC and CDA congruent? Justify your answer. brainly
Setler79 [48]
Yes
because they have the same volume

5 0
3 years ago
Read 2 more answers
N=4; 2i and 3i are zeros <br> f(-1)=50
Nonamiya [84]

Solution:- \text{Let f(x) be any nth degree polynomial with n=4}\\

\text{Given that 2i and 3i are the zeroes of f(x)}

\text{so (x-2i) and (x-3i) are factors of f(x)}

\text{Since 2i is a zero of f(x) then its conjugate -2i is also a zero of f(x)}

\Rightarrow(x+2i) \text{is a factor}\\\text{Similarly, conjugate of 3i is -3i is also a zero of f(x) }\\\Rightarrow(x+3i)\text{is a factor}\\\text{So , }\\f(x)=k(x-2i)(x+2i)(x-3i)(x+3i)\\=k(x^2-(2i)^2)(x^2-(3i)^2)\\=k(x^2-4i^2)(x^2-9i^2)\\=k(x^2+4)(x^2+9)\\=k(x^4+13x^2+36)\\\text{As given}\\f(-1)=50\\\Rightarrow k((-1)^4+13(-1)^2+36)=50\\\Rightarrow k(1+13+36)=50\\\Rightarrow k(50)=50\\\Rightarrow k=1\\\text{So by substituting k=1 in f(x) we get ,}\\f(x)=(x^4+13x^2+36)

6 0
3 years ago
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