First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
You solve this by using google.com or YouTube.com
Or just pay attention in class to get this.
Answer:
280 downloads
Step-by-step explanation:
-let x denote the number of standard version downloads.
-Given that the high-quality version was downloaded four times as often as the standard version it is denoted as 4x
-This can then be expressed as:
Hence, the number of standard version downloads is 280
Answer:
d
Step-by-step explanation:
(2m + 7) - (3 - 4m)
First distribute the (-) in front of the quantity of 3 - 4m.
Think of it as this:
-1(3 - 4m)
You multiply each number inside the parenthesis by -1.
So:
3*-1 = -3
-4m * -1 = 4m
Now that you've distributed the negative you can remove the parenthesis.
Now you'll just set it all up like you would any normal problem. Because -3 is negative you'll make it subtract.... I'll show you what I mean:
2m + 7 - 3 + 4m
Combine like terms (Terms which have the same variables... in this case the same number of m's)
Rearranging them can help!
4m + 2m + 7 - 3
6m + 7 - 3
6m + 4, is our difference!
