To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
<u>Rectangle (a)</u>
<u>Rectangle (b)</u>
<u>Rectangle (c)</u>
<u>Rectangle (d)</u>
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
9999
first 3 nines have the greater value but the first one has the highest and the least one is the last nine.
Answer:
3rd choice
Step-by-step explanation:
Add 6 to both sides to get 5x >= 15, or x >=3. This is the 3rd choice.
2.5 x 10 = 25 m^2
1.5 x 10 = 15 m^2
2 x 10 = 20 m^2
0.5 x 1.5 x 2 = 1.5 m^2 (2 times)
Total = 63 m^2
So just fill in 63.
Step-by-step explanation:
<h3>this is given that the figure is a hexagon</h3><h3>let give a name to the given hexagon be ABCDEF</h3>
<h3>Angle a + B + C + D = 720 ( Ls sum pro. of hexagon)</h3><h3>3x-20+3x-20+4x+4x+3x-20+3x-20 = 720</h3><h3>3x+3x+3x+3x+4x+4x-20-20-20-20 = 720 (rearranging)</h3><h3>20x - 80 = 720</h3><h3>20x = 720 + 80 </h3><h3>x=800/20</h3>
<h2>x = 40 degrees </h2>
<h3>3x-20 = 100</h3><h3>4x = 160</h3>
<h2>I HOPE THAT THIS ANSWER HELPS YOU</h2>
