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Gnom [1K]
2 years ago
9

Julio had $100 in account A on Sunday how much money does have in the account on Friday

Mathematics
2 answers:
yuradex [85]2 years ago
4 0

Answer:

there is no way to solve it

Step-by-step explanation:

i think you may have missed part of the question

Anestetic [448]2 years ago
3 0

Answer:

Not enough information

Step-by-step explanation:

julio had $100 in account | BLANK INFORMATION THAT IS REQUIRED |
A on Sunday how much money does have in the account on Friday

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Trapezoid JKLM is shown below.
Alecsey [184]
B is the answer because you have to math it
5 0
3 years ago
Please help!!!! Whoever answers these three questions correctly first will get brainliest answer!!!!!
inna [77]
4. -8
5. 24
6. I can't see it properly so if it's ÷ answer is 9 if it's - answer is -70
4 0
3 years ago
Read 2 more answers
Help I NEED HELP1 HELP HELP HELP HELP!
riadik2000 [5.3K]

Answer:

C. 18

Step-by-step explanation:

96 divided by 6 = 16

16+2=18

6 0
3 years ago
Which values are possible rational roots of 4x3+9x2−x+10=0 according to the rational root theorem? Select each correct answer. ±
navik [9.2K]

ANSWER


The possible rational roots are:


\pm\frac{1}{2},\pm2,\pm \frac{5}{2}


EXPLANATION


According to the rational root theorem, the possible rational roots of the polynomial,



4x^3+9x^2-x+10=0


are all the possible factors of the constant term divided by all the possible factors of the coefficient of the highest degree of the polynomial.



Therefore we examine the numerator and denominator of the options provided to see if they are factors of 10 and 4 respectively.



For

\pm\frac{1}{2}, we can see that 1 is a factor of 10 and 2 is a factor of 4, hence it is a possible rational root.


The same thing applies to \pm2,\pm \frac{5}{2} also.


As for


\pm \frac{2}{5}, 2 is a factor of 10 but 5 is not a factor of 2, hence it is not a possible rational root.


5 0
3 years ago
Please answer will give brainly
kotykmax [81]

Answer:

Step-by-step explanation:

The volume of a cube is given by the formula :

a³ (where a is the side length )

So now we have to cube these lengths :

Part A :

(3x²y)³ =

(3x²y)(3x²y)(3x²y) =

(9x^4y²)(3x²y) =

27x^6y³ (This is now fully simplified so our final answer for a)

Part B:  

(5y²)³ =

(5y²)(5y²)(5y²) =

(25y^4)(5y²) =

125y^6 (This is now fully simplified so our final answer for b)

Hope this helped and have a good day

5 0
1 year ago
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