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3 years ago

How much binding is needed to bind the edge of a circular rug that is 3m in diamter

Mathematics

2 answers:

Pavel [41]3 years ago

8 0

You multiply pi times 3m which equals 9.42

Anuta_ua [19.1K]3 years ago

5 0

You need to find the circumference

C= d x pi
C=3 x 3.14
C= 9.42

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Solve the formula for one of its variables using addition subtraction and/ or division

Sati [7]

One way of doing this would be to look at the πr² as if it were a single term. Then we could divide both sides by πr², which leaves h = V/πr².

3 0

2 years ago

13. Wind farms are a source of renewable energy found around the world. The power P (in kilowatts) generated by a wind turbine v

suter [353]

Since the Power is directly proportional to the velocity, their ratio $\frac{P}{v^{3} }$ is constant.

<span>Therefore </span> $\frac{500}{ 10^{3} } = \frac{x}{ 12^{3} }$ which is a proportion:

500 : 1000 = x : 1728

that can be easily solved:

x = (500×1728)/1000 = 864kW

8 0

3 years ago

Read 2 more answers

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

Help me out smartie pants hahahahaahahaha

MAXImum [283]

Answer:

5/8

I had it

4 0

3 years ago

Find the value of x.

olchik [2.2K]

Answer:

x = 4

Step-by-step explanation:

In $\triangle BAC, \: DE || AC$

Hence, by basic proportionality theorem:

$\frac{x + 2}{x} = \frac{3}{2} \\ \\ \therefore \: 2(x + 2) = 3x \\ \therefore \:2x + 4 = 3x \\ \therefore \:4 = 3x - 2x \\ \therefore \:4 = x \\ \huge \red { \boxed{\therefore \:x = 4}}$

7 0

2 years ago