4 years ago

Hi what is the answer for this?

2 answers:

6 0

I believe it's A I really hope that's right

4 0

I think it's A witch is the number 24

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serious [3.7K]

Mean is 27.4
Median is 22
Range is 27

Just use the mathematical definition of each word

7 0

4 years ago

Svetlanka [38]

Answer:

Step-by-step explanation:

5 0

3 years ago

Ivan

Well a million is 1,000,000,000. So 320,000,000,000 has 1" zeros

8 0

3 years ago

Leona [35]

3 0

4 years ago

Sladkaya [172]

I think factorizing everything you can first will make the simplification ... well, simpler.

$\dfrac{x^2 - 3x}{x^2 + 13x + 36} \div \dfrac{x^2+7x}{x^2+16x+63} = \dfrac{x(x-3)}{(x+4)(x+9)} \div \dfrac{x(x+7)}{(x+7)(x+9)}$

The factors of $x+7$ in the second rational expression cancel:

$\dfrac{x^2 - 3x}{x^2 + 13x + 36} \div \dfrac{x^2+7x}{x^2+16x+63} = \dfrac{x(x-3)}{(x+4)(x+9)} \div \dfrac{x}{x+9}$

Now, use the property

$\dfrac ab \div \dfrac cd = \dfrac ab \times \dfrac dc$

(this is the property of multiplication having to do with multiplicative inverse, or "inverting the divisor" as the question calls it) to write

$\dfrac{x^2 - 3x}{x^2 + 13x + 36} \div \dfrac{x^2+7x}{x^2+16x+63} = \dfrac{x(x-3)}{(x+4)(x+9)} \times \dfrac{x+9}x$

and we see some more cancellation, namely of the factors of $x$ and $x+9$ .

$\dfrac{x^2 - 3x}{x^2 + 13x + 36} \div \dfrac{x^2+7x}{x^2+16x+63} = \boxed{\dfrac{x-3}{x+4}}$

6 0

2 years ago