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olya-2409 [2.1K]
3 years ago
10

Hi what is the answer for this?

Mathematics
2 answers:
Marat540 [252]3 years ago
6 0
I believe it's A I really hope that's right
Margaret [11]3 years ago
4 0
I think it's A witch is the number 24
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What is the slope of a line perpendicular to the line:<br><br> y = -2/3x + 5
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1.5

Opposite reciprocal of -2/3

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Simplify the remaining expression completely x^6y^4/xy^2
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Step-by-step explanation:

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Hi there!

\large\boxed{ 9.4m}

Find the perimeter using the formula:

P = 2l + 2w

It is given that the dimensions are 2.8 × 1.9 so plug these number into the equation:

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2 years ago
If two of these shapes are randomly chosen, one after the other without replacement, what is the probability that the first will
aleksandrvk [35]

Answer:

P(T\ n\ S) = \frac{1}{14}

Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

Determine the probability of triangle being first then square being second

Total = 4 + 5 + 3 + 3

Total = 15

Represent the triangle with T and square with S

So, we're solving for P(T n S)

P(T\ n\ S) = P(T) * P(S)

Solving for P(T)

P(T) = \frac{n(T)}{Total}

P(T) = \frac{5}{15}

Solving for P(S)

The question implies a probability without replacement;

Hence Total has now been reduced by 1

Total = 14

P(S) = \frac{n(S)}{Total}

P(S) = \frac{3}{14}

Recall that

P(T\ n\ S) = P(T) * P(S)

P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}

P(T\ n\ S) = \frac{15}{15 * 14}

P(T\ n\ S) = \frac{1}{14}

Hence, the required probability is

P(T\ n\ S) = \frac{1}{14}

3 0
2 years ago
Choose where it is a function or not a function also choose what is the range and the domain
kow [346]
Not a function because of the vertical line test.
Domain is [-2,∞] since the left most point is -2 and the right is unbounded.
Range is (-∞,∞) since it is not bounded in terms of y.
7 0
2 years ago
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