Hi what is the answer for this?

Mathematics

2 answers:

Marat540 [252]3 years ago

6 0

I believe it's A I really hope that's right

Margaret [11]3 years ago

4 0

I think it's A witch is the number 24

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Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = n

ziro4ka [17]

These 2 equations has no solution and the equations are independent of each other.

<u>Step-by-step explanation:</u>

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

4 0

3 years ago

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Plz help on this math problem

tangare [24]

The answer I believe is the second one to the top

8 0

2 years ago

Everyone get off of social and help people on here! -_-

Marizza181 [45]

It's me..............

8 0

2 years ago

What is the solution to log2(2x^3-8)-2log2(x)=log2(x)

Charra [1.4K]

$\bf \textit{Logarithm of rationals}
\\\\
log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\\\
\textit{Logarithm of exponentials}
\\\\
log_a\left( x^b \right)\implies b\cdot log_a(x)\\\\
-------------------------------$

$\bf log_2(2x^3-8)-2log_2(x)=log_2(x)
\\\\\\
log_2(2x^3-8)-log_2(x^2)=log_2(x)\implies log_2\left( \cfrac{2x^3-8}{x^2} \right)=log_2(x)
\\\\\\
\textit{since both sides are getting }log_2\textit{ we can simply undo that}
\\\\\\
\cfrac{2x^3-8}{x^2}=x\implies 2x^3-8=x^3\implies x^3-8=0
\\\\\\
x^3=8\implies x=\sqrt[3]{8}\implies x=2$

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2 years ago

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What's equivalent to this polynomial: (10g^3-8g^2+5g-14)+(10g^2+12g)

ArbitrLikvidat [17]

<span>10g³+2g²+17g-14

Hope I helped! ( Smiles )</span>

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2 years ago