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3 years ago

2 3 + x = 3 what is X solved for

2 answers:

6 0

Hi there! My name is Zalgo and I am here to help you out on this wonderful day. "23+x=3", it seems that we need to find the "X value". That would be "-20". In order to test that it is the correct answer, just input it into the equation. "23+-20=3".

I hope that this helps! :)

"Stay Brainly and stay proud!" - Zalgo

(By the way, do you mind marking me as Brainliest? I'd greatly appreciate it! Thank you! XP)

Olegator [25]3 years ago

5 0

Answer:

Obviously its x=3-23=-20.

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Step-by-step explanation:

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3 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

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3 years ago

Determine the coordinates of the triangle shown below after a dilation with a scale factor of 4

tatyana61 [14]

Do you have the picture?

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3 years ago

Jake has 6 quarters 2 dimes and a nickel does he have enough to buy a dog bone that costs 1.49?

Darina [25.2K]

Answer:

Jake does have enough to buy a dog bone that cost $1.49

Step-by-step explanation:

6 quarters = $1.50

2 dimes = $0.20

1 nickel = $0.05

So add it all together: $1.50 + $0.20 + $0.05 = $1.75

7 0

2 years ago