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dusya [7]
3 years ago
15

SHOW STEP BY STEP PLEASE HELP ME

Mathematics
2 answers:
dybincka [34]3 years ago
8 0

Yo sup??

You can solve this question by directly applying the distance formula which is given by

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where x1,y1=-3,1

and x2,y2=5,6

plugging in the values

d=\sqrt{(-3-5)^2+(1-6)^2}\\ =\sqrt{64+25}\\ =\sqrt{89}\\=9.4

I hope this helps.

Ainat [17]3 years ago
3 0

Answer:

9.4 units

Step-by-step explanation:

So first we need to create a right angled triangle so that we can use Pythagoras theorem.

The difference in y = 6 - 1 = 5

The difference in x = 5 - -3 = 8

Finding the length of line segment CD is like finding the magnitude or the hypotenuse. So:

CD² = 8² +5²

CD² = 64 + 25

CD² = 89²

CD = √89

CD = 9.4

Because we aren't given any units we leave it as 9.4 units or just 9.4

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Answer:

y - 27 = 0 (x - 21) or y = 27

Step-by-step explanation:

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3 years ago
Solve: <br><br> 4(n-7) -2 (n+3)-15n
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Answer:

solved

Step-by-step explanation:

4n-28 -2n -6 -15n

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3 years ago
Congress regulates corporate fuel economy and sets an annual gas mileage for cars. A company with a large fleet of cars hopes to
attashe74 [19]

Answer:

a) Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

b) X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c) t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

p_v =P(t_{(49)}>2.81)=0.0035  

d) If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e) The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

\bar X=32.12 represent the sample mean  

s=4.83 represent the sample standard deviation

n=50 sample size  

\mu_o =30.2 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

a. Define the parameter and state the hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 30.2 mpg, the system of hypothesis would be:  

Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

b. Define the sampling distribution (mean and standard deviation).

Let X the random variable who represent the variable of interest. And we know that the distribution for X is:

X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c. Perform the test and calculate P-value

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=50-1=49  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(49)}>2.81)=0.0035  

d. State your conclusion.

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e. Explain what the p-value means in this context.

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

6 0
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Can I get help with this please?
sammy [17]
First equation:
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5x+5=20 ——- subtract 5 from 20
5x=15 ———— divide by 5 from both sides
X=3 ————— answer

Second equation:
5x+1=20——— subtract 1 from 20
5x=19 ———— divide by 5 from both sides
X=19/5———— answer in fraction form
X=3.8————- answer in decimal form
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Mr. Arnold drives 130 miles round trip to work 5 days a week. Write and solve an equation to find how many miles he drives in 60
mart [117]

Answer:

The answer is D.

Step-by-step explanation:

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