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2 years ago

If sin theta < 0 and tan theta > 0 then

1 answer:

7 0

If sin theta < 0 and tan theta > 0 as described in the task content, then, cos theta < 0 and 180<theta <270.

<h3>What is correct about angle theta as described?</h3>

From the task content, it was described that sin theta < 0 and tan theta > 0.

Upon recall of angle quadrants, it follows that only the 3rd quadrant angles have positive tan values and negative sin values. Hence, it follows that the angle theta is in the 3rd quadrant and also has cos theta < 0.

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Please help with these two math problems<br><br> 1. 7^x ÷ 7^y =<br> 2. z^10x^y ÷ z^5 =

IceJOKER [234]

Answer:

1. 7^(x-y)

2. z^5x^y

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)/(a^c) = a^(b-c)

$\dfrac{7^x}{7^y}=\boxed{7^{x-y}}$

$\dfrac{z^{10}x^y}{z^5}=x^yz^{10-5}=\boxed{z^5x^y}$

8 0

3 years ago

Write an expression that represents the area of a circle with radius 3x^3. (For any circle with radius r, a=π r^2 = π .r .r ^.)

aalyn [17]

9514 1404 393

Answer:

B. 9πx^6

Step-by-step explanation:

Putting the given radius into the area formula gives ...

A = πr^2

A = π(3x^3)^2 = π(3^2)(x^(3·2))

A = 9πx^6

6 0

3 years ago

25 points!! please answer

melomori [17]

ac is the answer

hope that helps

6 0

3 years ago

Read 2 more answers

PLEASE HELP 50 POINTS

natima [27]

Answer:

C. 1/3<b<3/2

D. 1/6<x<2

Step-by-step explanation:

Hope this helps

3 0

2 years ago

Read 2 more answers

Find the value of x such that 365 based seven + 43 based x = 217 based 10.

Pepsi [2]

We need to find the base x in the following equation:

$365_7+43_x=217_{10}$

First, lets convert 365 from base 7 to base 10. This is given by

$365_7=3\times7^2+6\times7^1+5\times7^0$

where the upperindex denotes the position of eah number. This gives

$\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}$

that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

$43_x=4\times x^1+3\times x^0$

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

$43_x=(4x+3)_{10}$

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

$194_{10}+(4x+3)_{10}=217_{10}$

For simplicity, we can omit the 10 and get

$194+4x+3=217$

so, we can solve this equation for x. By combining similar terms. we have

$197+4x=217$

and by moving 197 to the right hand side, we obtain

$\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}$

Finally, we get

$\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}$

Therefore, the solution is x=5

8 0

1 year ago