Answer:
See below.
Step-by-step explanation:
a.
x = cost of adult ticket
y = cost of student ticket
cost of adult ticket is twice the cost of a student ticket
x = 2y
number of adult tickets = 64
number of student tickets = 132
cost of all adult tickets = 64x
cost of all student tickets = 132y
cost of all adult and student tickets combined: 64x + 132y
cost of all adult and student tickets combined: 1040
This gives us the equation:
64x + 132y = 1040
b.
Use substitution to solve the system of equations. Since x = 2y, where you see x in the second equation, substitute it with 2y.
64(2y) + 132y = 1040
128y + 132y = 1040
260y = 1040
y = 1040/260
y = 4
x = 2y = 2(4) = 8
adult ticket: $8
student ticket: $4
1 and 2 both have 1/4th slope, (2 is y=.25x +2.8)
3 has 1/4th slope, (y = 1/4x - 8/5)
4 has a -1/4th slope.
H would be correct as all the others have a 1/4th slope and IV is only one with a -1/4th slope
I think its b but im not sure
Confused on this question
Y = -3x + 5
5x - 4y = -3
5x - 4(-3x + 5) = -3
5x + 4(3x) - 4(5) = -3
5x + 12x - 20 = -3
17x - 20 = -3
+ 20 + 20
17x = 17
17 17
x = 1
y = -3x + 5
y = -3(1) + 5
y = -3 + 5
y = 2
(x, y) = (1, 2)