Answer:
x = 2
Step-by-step explanation:
The parallel lines divide the transversals in proportion, that is
=
=
( cross- multiply )
4x = 8 ( divide both sides by 4 )
x = 2
Step-by-step explanation:
the ratio of the pool lengths is 3/5.
that means for every 3 meters of length on Shantel's pool, there are 5 meters of length on Juan's pool.
it the other way around : to get to the size of Shantel's pool, every 5 meters of length on Juan's pool are converted to 3 meters.
x = length of Juan's pool
x × 3/5 = 30
3x = 150
x = 50 meters
you see the relationship ?
3/5 = 30/50 = 300/500 = ...
but it is true for any factor
3/5 = 15/25 = 24/40 = 6/10 = ...
once you see the factor for one part of the ratio, you know there is the same factor for the other part (or parts) of the ratio. otherwise the ratio would not stay the same and keep the relationship.
The answer is $1.80. You would take 25% of 3, which is 75, and subtract it from 3. That leaves you with $2.25, which you take 20% off, which is 0.45, and subtract that from 2.25. That leaves you with a grand total of $1.80. Hope that this helped!
Answer:
£20.44
Step-by-step explanation:
Step 1: find the area of the total area of the garden.
Total area = l*w
Where,
l = 10 m
w = 6 m
Total area of garden = 10*6 = 60m²
Step 2: find the area of the vegetable patch.
Area of vegetable patch = l*w = 2*1.5 = 3m²
Step 3: find the area covered by pond.
Area covered by pond = πr²
Take π as 3.14
r = 2m
Area of pond = 3.14*2² = 12.56 m²
Step 4: find the area of the remainder of the garden to be reseeded.
Area of the remainder of the garden = total area of the garden - (area of the vegetable patch + area of pond)
= 60 - (3 + 12.56)
= 60 - 15.56
Area of the remainder of the garden = 44.44 m²
Step 5: calculate the total cost to reseed the garden.
Given that a bag of seed to cover 10m² is £4.60, total cost to reseed the remainder of the garden measuring 44.44 m² can be calculated bas follows:
10 m² = £4.60
44.44 m² = 
The answer is £20.44
Answer:
D should be the right answer since the line on the graph goes from negative infinity to positive infinity, and all real numbers are included