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Elodia [21]
3 years ago
10

¿por que la toria de lamarck sobre el alargamiento del cuello de las jirafas por el esfuerzo continuado no pasara a sus descendi

entes? Porfa es ciencia y ambiente estoy en el peru
Computers and Technology
1 answer:
Paha777 [63]3 years ago
7 0

Respuesta: Los caracteres adquiridos no se transmiten genéticamente porque no modifican el ADN de los organismos

Explicación:

Jean-Baptiste Lamarck al igual que Charles Darwin, propuso una teoría sobre la evolución que explicaba cambios en los organismos a través del tiempo. La teoría de Lamarck se enfocaba en condiciones en el ambiente que propiciaban cambios en los organismos. Un ejemplo de esto son las jirafas, que de acurdo a Lamarck tenían cuellos largos debido al esfuerzo continuado para comer hojas de árboles altos. Esto significa que la característica de cuello largo era adquirido por las jirafas durante su vida y según Lamarck se transmitiría a sus descendientes.

Sin embargo, se ha comprobado que los caracteres adquiridos no modifican el ADN de los organismos, por ejemplo las cirugías estéticas no cambian el ADN de una persona y por esta razón no son transmitidos a sus descendientes. Por el contrario, en las poblaciones de organismos ciertas características prevalencen en el tiempo debido a la selección natural. Esto significa que el cuello de las jirafas es el resultado que el cuello largo sea una característica beneficiosa que ha prevalecido debido a la selección natural y no de características adquiridas que son transmitidas a descendientes.

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Answer:

This question is answered using C++

#include<iostream>

#include <cstdlib>

#include <ctime>

using namespace std;

int main(){

   int ope, yourresult;

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   cout<<"Operator: ";

   cin>>ope;

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   int num2 = rand() % 12;

   int result = 1;

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   else if(ope == 2){

       cout<<num1<<" - "<<num2<<" = ";

       result = num1 - num2;

   }

   else if(ope == 3){

       cout<<num1<<" * "<<num2<<" = ";

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   }

   else{

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   cin>>yourresult;

   if(yourresult == result){

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   }

   return 0;

}

Explanation:

This line declares operator (ope) and user result (yourresult) as integer

   int ope, yourresult;

This prints the menu

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

This prompts the user for operator

   cout<<"Operator: ";

This gets user input for operator

   cin>>ope;

This lets the program generates different random numbers

   srand((unsigned) time(0));

This generates the first random number

   int num1 = rand() % 12;

This generates the second random number

   int num2 = rand() % 12;

This initializes result to 1

   int result = 1;

If the operator selected is 1 (i.e. addition), this prints an addition operation and calculates the actual result

<em>    if(ope == 1){</em>

<em>        cout<<num1<<" + "<<num2<<" = ";</em>

<em>        result = num1 + num2;</em>

<em>    }</em>

If the operator selected is 2 (i.e. subtraction), this prints an subtracttion operation and calculates the actual result

<em>    else if(ope == 2){</em>

<em>        cout<<num1<<" - "<<num2<<" = ";</em>

<em>        result = num1 - num2;</em>

<em>    }</em>

If the operator selected is 3 (i.e. multiplication), this prints an multiplication operation and calculates the actual result

<em>    else if(ope == 3){</em>

<em>        cout<<num1<<" * "<<num2<<" = ";</em>

<em>        result = num1 * num2;</em>

<em>    }</em>

If selected operator is not 1, 2 or 3, the program prints an invalid operator selector

<em>    else{</em>

<em>        cout<<"Invalid Operator";</em>

<em>    }</em>

This gets user input

   cin>>yourresult;

This checks if user result is correct and prints "Correct!"

   if(yourresult == result){

       cout<<"Correct!";

   }

If otherwise, the program prints "Incorrect!"

<em>    else{</em>

<em>        cout<<"Incorrect!";</em>

<em>    }</em>

   return 0;

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