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3 years ago

A password contains 2 letters and 3 digits. How many passwords are possible if

Mathematics

2 answers:

pentagon [3]3 years ago

7 0

Im pretty sure the answer is 12 or 13

Keith_Richards [23]3 years ago

6 0

Answer:

i think it is 12 but i could be wrong

You might be interested in

For the graphed function f(x) = -(5)* - 3 + 2, calculate the average rate of change from x = 3 to x = 4.

Ilia_Sergeevich [38]

Answer:

-4

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is $\frac{f(b)-f(a)}{b-a}$

The given function is $f(x)=-5^{x-3}+2$ .

$f(4)=-5^{4-3}+2=-3$ .

$f(4)=-5^{3-3}+2=1$ .

The average rate of change from x=3 to x=4 is given by:

$\frac{f(4)-f(3)}{4-3}$

$\frac{-3-1}{4-3}=-4$

7 0

3 years ago

Assume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 20. Find the prob

Ipatiy [6.2K]

Answer:

Randomly selected adult has an IQ less than 136 is 0.9641

Step-by-step explanation:

It is given that, it is normal distribution with mean 100 and SD as 20.

So, let's use the formula of z-score

z= $\frac{x-mean}{SD}$

For this problem,

x= 136

Plug in this value into the formula

z-score= $\frac{136-100}{20}$

=1.8

Now, use z-score table to find the probability

Find the corresponding value for the row 1.8 and the column 0.00, we do get 0.9641

So, Randomly selected adult has an IQ less than 136 is 0.9641

3 0

3 years ago

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.