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3 years ago

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Given z=f(x,y),x=x(u,v),y=y(u,v), with x(4,1)=5 and y(4,1)=2, calculate zv(4,1) in terms of some of the values given in the tabl

e below.

1 answer:

Yuliya22 [10]3 years ago

3 0

$z=f(x(u,v),y(u,v))\implies z_v=f_xx_v+f_yy_v$

$z_v(4,1)=f_x(5)x_v(4,1)+f_y(2)y_v(4,1)$

No table = incomplete answer

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15 3/14+ 24 1/14+ 12 2/7+ 12 2/7+ 10 1/7 +10 1/7+ 35 3/7=

lesantik [10]

Answer:

it is :119.5714

Step-by-step explanation:

15 3/14+24 1/14+12 2/7+12 2/7+10 1/7+10 1/7+35 3/7=

step by step now:

15 3/14+24 1/14+12 4/14+12 4/14+10 2/14+10 2/14+35 6/14=118 22/14=118+1.5714=119.5714

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Read 2 more answers

Solve for x: −3|2x + 6| = −12

spayn [35]

Start with

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