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Black_prince [1.1K]

4 years ago

14

What is the y-intercept of the line that is the perpendicular bisector of the segment joining (-3,-4) and (5,10)? express you an

swer as a mixed number?

1 answer:

Novosadov [1.4K]4 years ago

7 0

My geometry program shows the equation of the bisector to be
.. 4x +7y = 25
When x = 0, the y-value is 25/7 = 3 4/7

The y-intercept is 3 4/7.

You might be interested in

following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in

valina [46]

<em>Note:</em> <em>As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.</em>

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

<em>Daily expenditure on milk (in Rs) Number of households</em>

<em> 0-30 5</em>

<em> 30-60 6 </em>

<em> 60-90 9</em>

<em> 90-120 6</em>

<em> 120-150 4</em>

Here the maximum frequency is 9.

So, modal class is <em>60-90.</em>

<em />

As the formula to calculate the mode:

$Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )$

Here, the maximum

$l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30$

$l=$ is the lower limit of the class

$f_{1} =$ is the frequency of the modal class

$f_{0} =$ is the frequency of the previous modal class

$f_{2} =$ is the frequency of the next previous modal class

$l=$ is the class size

So,

$Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )$

$Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )$

$Mode = 60 + \frac{(30)(3)}{6}$

$Mode = 60 + 15=75$

∴ The mode of the data = 75

<em>Keywords: mode, frequency distribution</em>

<em> Learn more about mode and frequency distribution from brainly.com/question/14354368</em>

<em> #learnwithBrainly </em>

5 0

3 years ago

If someone could please help me I really need help me with geometry

iVinArrow [24]

Answer:

VU = 8

KL = 19

ΔS = 120°

ΔF = 130°

HOPE IT HELP

PLZ FOLLOW ME

8 0

3 years ago

Helppppp quick plz

Andreyy89

Answer:

C. (35, 3.5)

Step-by-step explanation:

its the only pair that is on the line

35 is the x-axis and 3.5 is the y-axis so you go to 35 then up to 3.5 and the pair is on the line

4 0

3 years ago

Explain when you must write the number 1, and when you do not need to.

stepan [7]

Answer:

The number 1 is not necessary when expressing powers of one. For example, you needn't write "5" as $5^{1}$ .

Step-by-step explanation:

7 0

3 years ago

Consider parallel lines cut by a transversal.

Cerrena [4.2K]

When two parallel lines are cut by a transverse. the angles formed on the exterior of the parallel lines, on the opposite sides of the transverse are known as the Alternate Exterior Angle.

<h3>What are Alternate exterior angles?</h3>

When two parallel lines are cut by a transverse. the angles formed on the exterior of the parallel lines, on the opposite sides of the transverse are known as the Alternate Exterior Angle.

Firstly, ∠1 and ∠7 are alternate exterior angles as shown in the image, now to prove if these two angles will be congruent we can use the below proof.

First Method:

∠1 + ∠2 = 180° {Supplementary angles because both lies on the line q}

∠2 = (180° - ∠1)

Similarly, ∠2 = ∠6 = (180° - ∠1), corresponding angles are equal,

∠6 + ∠7 = 180° {Supplementary angles because both lies on the line r}

∠7 = 180° - ∠6

∠7 = 180° - (180° - ∠1)

∠7 = 180° - 180° + ∠1

∠7 = ∠1

OR

Second Method:

∠1 = ∠3 {Vertical angles formed by intersecting lines q and r}

∠3 = ∠5 {Alternate Interior angles}

∠5 = ∠7 {Vertical angles formed by intersecting lines s and r}

Learn more about the Alternate Exterior Angles:

brainly.com/question/14693114

#SPJ1

5 0

2 years ago