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3 years ago

Given the vertex (2,9) and the foci (5,9), what is the equation of the directrix

Mathematics

1 answer:

Gennadij [26K]3 years ago

6 0

Answer:

x = -1

Step-by-step explanation:

The vertex is halfway between the focus and the directrix.

So here the directrix is a vertical line to the left of the vertex and passing through the point (2-3, 9) = (-1, 9)

It is x = -1.

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Tasya [4]

Answer:

$2.11

Step-by-step explanation:

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3 years ago

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

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3 years ago

Please help me outtttttttttt

Evgen [1.6K]

Answer:

is correct

Step-by-step explanation:

1/12

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3 years ago

What is the algebraic solution to the function 2x+3=83

nirvana33 [79]

3-83= 80
80 divided by 2 is 40
the answer is 40

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Nimfa-mama [501]

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4 years ago

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