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Harlamova29_29 [7]
3 years ago
15

Joe first focuses his attention (and his eyes) on the tree. The focal length of the cornea-lens system in his eye must be ______

____ the distance between the front and back of his eye.
a. greater than
b. less than
c. equal to

Physics
2 answers:
Grace [21]3 years ago
6 0

Answer:

Joe first focuses his attention (and his eyes) on the tree. The focal length of the cornea-lens system in his eye must be __________ the distance between the front and back of his eye.

The answer is option B (less than)

Explanation:

The cornea which is the strongest part of the refracting power of the eye, is the front part of the eye, and the backside of the eye is called retina.

Light enters the eye at the curved front surface of the cornea, passes through the lens, and then strikes the retina and fovea on the back of the eye. For the eye to receive light, light travels in air, gets refracted majorly at the cornea with some other refraction done by the Aqueous humor, the lens and the vitreous humour. Focal length of the lens must vary to ensure objects at various distance can be brought to a focus at the retina.

When the effective focal length of the cornea-lens system  changes, it changes the location of the image of any object in one's field of view. The fovea which is a small area near the center of the retina, is responsible for the most acute vision. Speed of light changes considerably while traveling from air into cornea.

When muscles in the eye contract and squeeze the lens, the center of the lens bulges, causing the focal length to shorten, and allowing the eye to focus on closer objects. The image distance depends on both the object distance and the focal length of the lens. For objects to be at infinity the focal point must be situated farthest from the lens, while near objects have focal point closer to the lens.

nexus9112 [7]3 years ago
4 0

Answer:

The correct answer is letter b. less than

Explanation:

In the attached schematic figure, the lens (lens) is initially adjusted for a given distance from the object. If the object gets closer, the image loses its sharpness. To recover it, the lens settles down, increasing convergence, that is, decreasing the focal length.

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6 0
4 years ago
A rubber ball is dropped from a height of 8m. After strikingthe floor, the ball bounces to a height of 5m. a. If the ball had bo
kifflom [539]

Answer:

a) This means the collision between the ball and the floor is elastic.

b) This points to a perfectly inelastic collision between the ball and the floor as they stick together after collision

c) Check Explanation.

Explanation:

Collision of bodies are analysed according to whether both momentum and kinetic energy of the system is conserved, that is, if these two quantities before collision are equal to their values after collision.

In all types of collisions, momentum is usually conserved, but kinetic energy is conserved only in an elastic collision.

A ball dropped from a height of 8 m bounces up back to a height of 5 m.

a. If the ball had bounced to a height of 8m, how would you describe the collision between the ball and the floor?

The ball not bouncing back to a height of 8 m shows energy loss at some point in the total motion of the ball (most likely at the collision). If kinetic energy was conserved, the ball would bounce back up to the height at which it fell from (8 m) after the collision with the floor.

b. If the ball had not bounced at all, how would you describe the collision between the ball and the floor?

If the ball had not bounced at all, this means it lost all of its kinetic energy to the floor, and this points to a perfectly inelastic collision between the ball and the floor as they stick together after collision.

c. What happened to the energy lost by the ball during thecollision?

The energy lost during the collision is converted to another form, most likely responsible for some deformation on the ball & a minute deformation on the floor, converted to some form of heat as a result of the collision or into sound energy, usually, it's a combination of all This!

Hope this Helps!!!

5 0
4 years ago
Two converging lenses are separated by 27.0 cm. The focal length of each lens is 8.90 cm. An object is placed 33.0 cm to the lef
Ymorist [56]

Answer:

1/i + 1/o = 1/f     thin lens equation

i = 33 * 8.9 / (33 - 8.9) = 12.2 cm  to right of first lens

27 - 12.2 = 14.8 cm to left of second lens

i = 14.8 * 8.9 / (14.8 - 8.9) = 22,3 cm to right of second lens

7 0
3 years ago
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Maksim231197 [3]

Answer:

Only there will be a change in density of sun.

Explanation:

As your question says only the radius of sun is decreased and there is no change in the mass. So it means that the center of gravity will be the same and as a result the gravitational force remains the same. Only the density of sun changes as it shrinks.

8 0
3 years ago
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