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zepelin [54]
3 years ago
13

A 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7 N. What is the acceleration of the box?

Physics
1 answer:
Marysya12 [62]3 years ago
3 0

Answer:

F=ma

a=F/m=9.7N/5.5Kg=1.8 m/s^2

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