Hello! So the low and high whiskers consists of 1 and 10. A has 1 in the data, but not 10. A is eliminated. C has 10 in the data, but does not have one. That eliminates answer choice C. B has 1 and 10 as the data. Let's put the data of the numbers in order and see what happens.
1, 3, 4, 5, 5, 8, 9, 9, 9, 10
Let's cross out numbers from each end of the line to find our median. When we do this, we see that 5 and 8 are the middle numbers. In this case, we add the numbers and divide by 2. 5 + 8 is 13. 13/2 is 6.5 There. The median in the data is 6.5, and the box-and-whisker plot shows 6.5 as the median. There's a chance that ti could be it. But let's solve for the lower quartile. Draw a line between the 5 and 8. Start of by crossing out the 1 and 5 on opposite sides on the half. We see that the lower quartile is 4. Repeat the same step for the opposite half to find the third quartile, and the third quartile is 9. 4 and 9 are both shown as the quartiles in the box and whisker plot. B shows the correct data for the plot shown above. The answer is B.
There is a difference of 14 units between -2 and 12. To find the coordinate in the middle, just add 7, half the distance between -2 and 12, to -2 and subtract 7 from 12. That gives you the coordinate 5.
D again because as you can see....it does not touch the x axis at all, but the y axis is at -8
