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3 years ago

What is the difference between "x times x" and "x plus x"?

Mathematics

2 answers:

tankabanditka [31]3 years ago

7 0

Well, it's multiplication and addition.
They use different operations.

Mumz [18]3 years ago

3 0

Well first off x times x is squaring whatever the number is while x plus x is just multiplying by 2

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Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

Compound Inequalities <br> (Help)

sladkih [1.3K]

- 8x + 44 ≥ 60
- 8x ≥ 60 - 44
- 8x ≥ 16
x ≤ - 2

- 4x + 50 < 58
- 4x < 58 - 50
- 4x < 8
x > - 2

Now put the two together. Logically, these two answers since a number cannot be both less than AND greater than - 2.

Your answer should be no solution.

5 0

3 years ago

Solve the problem. Round the solution to the nearest hundredth where applicable. What is the tangent of ZH?

kumpel [21]

B because tangent is Opposite/hypotenuse. = 6/8 = 0.75

6 0

3 years ago

Please help me with number 6

Genrish500 [490]

30=(10*3*x)/2
*2 *2
60=10*3*x
60=30x
60/30=30x/30
2=x

7 0

3 years ago

It was John's birthday, 1/2 of his cupcakes were choco lava, the other half was strawberry. There were 10 strawberry cupcakes. R

igomit [66]

If there were 10 strawberry cupcakes then chocolate would have the same number as 10= 1/2. Then 2/4 can be simplified to 1/2 meaning that Rick are 1/2 of 10 and 1/10 is just one out of the 10 strawberry cupcakes.

Rick ate 5 Chocolate Cupcakes

Steward are 1 Strawberry Cupcake

4 0

3 years ago

Read 2 more answers