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3 years ago

5

What is the difference between "x times x" and "x plus x"?

2 answers:

tankabanditka [31]3 years ago

7 0

Well, it's multiplication and addition.
They use different operations.

Mumz [18]3 years ago

3 0

Well first off x times x is squaring whatever the number is while x plus x is just multiplying by 2

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Plz help I need it!!!!!!!!!!!!

AlekseyPX

Answer:

114°

Step-by-step explanation:

$? = \frac{1}{2} (53 \degree + 175 \degree) \\ \\ ? = \frac{1}{2} \times 228 \degree\\ \\ ? = 114 \degree$

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2 years ago

How do I do Distance Formula? Here is the equation ( or equations I don't know if it is a equation or 2 different ones) that I n

neonofarm [45]

Answer: view image below

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

Which values are solutions to the inequality below? √x ≤ 5

Romashka [77]

$\sqrt{x} \leq 5$

Find the real region for $\sqrt{x}$

$\sqrt{x}$ is real for $x \geq 0$

$= x \geq 0$

$\sqrt{x} \leq 5$

Square both sides:

$( \sqrt{x} )^2 \leq 5^2$

$5^2 = 5*5 =25$

Refine:

$x \leq 25$

Answer D

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5 0

3 years ago

(Brainliest for fastest right answer!!) Which is correct?

Arisa [49]

Answer:

<em>(n - 5)(n + 5) </em>

Step-by-step explanation:

a² - b² = (a - b)(a + b)

n² - 25 = n² - 5² = <em>(n - 5)(n + 5)</em>

7 0

2 years ago

What are the solutions of the quadratic equation? 4x^2+34x+60=0

insens350 [35]

Answer:

Option 3) -6,-5/2

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$4x^{2} +34x+60=0$

so

$a=4\\b=34\\c=60$

substitute in the formula

$x=\frac{-34(+/-)\sqrt{34^{2}-4(4)(60)}} {2(4)}$

$x=\frac{-34(+/-)\sqrt{196}} {8}$

$x=\frac{-34(+/-)14} {8}$

$x_1=\frac{-34(+)14} {8}=-\frac{20}{8}=-\frac{5}{2}$

$x_2=\frac{-34(-)14} {8}=-6$

6 0

2 years ago