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3 years ago

What is jk? Please help asap!!!

Mathematics

1 answer:

RSB [31]3 years ago

4 0

Answer:

20 m

Step-by-step explanation:

We can see from the hatch marks that JK is equal to one half of HG

2(6x - 4) = 10x

12x - 8 = 10x

2x - 8 = 0

2x = 8

x = 8/2

x = 4

therefore to find JK we will substitute x with 4

JK = (6(4)-4) = 24 - 4 = 20m

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=18 miles

HOPE THIS WILL HELP YOU

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3 years ago

A bin of 50 manufactured parts contains 3 defective parts and 47 non-defective parts. A sample of size 6 parts is selected from

lyudmila [28]

Answer:

535,095 different samples of size six that contain exactly 2 defective parts.

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

As the order of the parts is not important, the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many different samples are there of size six that contain exactly 2 defective parts?

2 defective from a set of 3, and 4 non-defective from a set of 47. So

$D = C_{3,2}*C_{47,4} = \frac{3!}{2!1!}*\frac{47!}{4!43!} = 535095$

535,095 different samples of size six that contain exactly 2 defective parts.

What is the probability that a sample contains exactly 2 defective parts?

The total number of samples is:

$T = C_{50,6} = \frac{50!}{6!44!} = 15890700$

Then...

$p = \frac{D}{T} = \frac{535095}{15890700} = 0.0337$

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

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3 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

Successful implementation of a new system is based on three independent modules. Module 1 works properly with probability 0.9, M

olga nikolaevna [1]

Answer:

The probability is 0.5086

Step-by-step explanation:

The probability P that at least one of these three modules will fail to work properly is calculated as:

P = 1 - P'

Where P' is the probability that all the modules works properly. So, P' os calculated as:

P' = 0.9 * 0.84 * 0.65

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Because 0.9 is the probability that module 1 works properly, 0.84 is the probability that module 2 works properly and 0.65 is the probability that module 3 works properly.

Finally, the probability P that at least one of these three modules will fail to work properly is:

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4 years ago