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allsm [11]
2 years ago
9

a student has some $1 bills and $5 bills in his wallet. he has a total of 15 bills that are worth $47. How many of each type of

Bill does he have. (using algebra, substitution to solve a problem)
Mathematics
2 answers:
Ipatiy [6.2K]2 years ago
8 0

Answer:  The student has 7 $1 bills and 8 $5 bills.

Step-by-step explanation:  Give that a student has some $1 bills and $5 bills in his wallet. He has a total of 15 bills that are worth $47.

We are to find the number of each type of bills that he has.

Let m and n represents the number of $1 bills and $5 bills respectively.

Then, according to the given information, we have

m+n=15\\\\\Rightarrow m=15-n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

1\times m+5\times n=47\\\\\Rightarrow m+5n=47\\\\\Rightarrow 15-n+5n=47\\\\\Rightarrow 4n=47-15\\\\\Rightarrow 4n=32\\\\\Rightarrow n=\dfrac{32}{4}\\\\\Rightarrow n=8.

From equation (i), we get

m=15-8=7.

Thus, the student has 7 $1 bills and 8 $5 bills.

Alenkasestr [34]2 years ago
6 0
The student would have 8 $5 bills and 7 $1 bills because 5*8=40 and 7*1=7 and adding them together makes 47! Hope that helps!
 
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Long division is often considered one of the most challenging topics to teach. Luckily, there are strategies that we can teach to make multi-digit division easier to understand and perform.

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