Answer:
<h3>
The width (side perpedicular to the barn):
<u>x = 8 m</u></h3><h3> The lenght (side parallel to the barn):
<u>y = 16 m</u> </h3>
Step-by-step explanation:
x - the width of the barn
She has 32 m of fencing so for the lenght remain (32-2x) m of fencing:
y = 32 - 2x
Area of the fencing: A = x•y
A(x) = x•(32 - 2x)
A(x) = -2x² + 32x ← quadratic function
The maximum value of quadratic function occurs at: 
a = -2, b = 32
32-2x = 32 - 2•8 = 16
Answer:
7
Step-by-step explanation:
20 • 35% = 13 20-13=7
1 foot is 12 inches. So just divide 81 by 12.
81/12 = 6.75
So your answer is 6.75 feet.
Answer:
4
Step-by-step explanation:
8x=32
x = 4
Problem 4
a)
MR = AG is a true statement because MARG is an isosceles trapezoid. The diagonals of any isosceles trapezoid are always the same length.
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b)
MA = GR is false. Parallel sides in a trapezoid are never congruent (otherwise you'll have a parallelogram).
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c)
MR and AG do NOT bisect each other. The diagonals bisect each other only if you had a parallelogram.
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Problem 5
a)
LC = AJ (nonparallel sides of isosceles trapezoid are always the same length)
x^2 = 25
x = sqrt(25)
<h3>x = 5</h3>
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b)
LU = 25
UC = 25 because point U cuts LC in half
LC = LU+UC = 25+25 = 50
AJ = LC = 50 (nonparallel sides of isosceles trapezoid are always the same length)
AS = (1/2)*AJ
AS = (1/2)*50
<h3>AS = 25</h3>
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c)
angle LCA = 71
angle CAJ = 71 (base angles of isosceles trapezoid are always congruent)
(angleAJL)+(angleCAJ) = 180
(angleAJL)+(71) = 180
angle AJL = 180-71
<h3>angle AJL = 109 </h3>
