Let f(x)=x2 - 4x - 7 and g(x)=x-3 fins f(g(x))

1 answer:

6 0

Answer: x^2 - 10x + 14

Explanation:

f(g(x))
= f(x-3) Since g(x) = x-3

And f(x) = x^2 - 4x - 7

=> f(x-3) = (x-3)^2 - 4(x-3) - 7
=> f(x-3) = x^2 - 6x + 9 - 4x + 12 - 7
=> f(x-3) = x^2 - 10x + 14

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