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2 years ago

I have a question here.

Mathematics

1 answer:

aniked [119]2 years ago

5 0

Answer:

3 ways

Step-by-step explanation:

n = 3; r = 2

$nC_{r}=\dfrac{n!}{r!(n-r)!}\\\\3C_{2}=\dfrac{3!}{2!1!}=\dfrac{3*2*1}{2*1}=3$

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What value(s) of x make the following expression undefined? x^2+ 1

allsm [11]

Answer:x=2

Step-by-step explanation: 2x-4=0

2x-4=0

+4 +4

2x=4

2x/2=4/2

X=2

5 0

3 years ago

What is the approximate diameter of a tire that will make 775 complete rotations in one mile? (Note: there are 5280 feet

GalinKa [24]

Answer:

About 2.17 feet.

Step-by-step explanation:

Let <em>d</em> represent the diameter of the tire.

Then the circumference of the tire will be:

$C=d\pi$

So, the tire will travel dπ miles after one rotation.

After 775 rotations, the total miles traveled should be 5280 feet. Thus:

$775(d\pi)=5280$

Solve for <em>d:</em>

<em /> $\displaystyle d=\frac{5280}{775\pi}$ <em />

Approximate:

$d=2.1686...\approx2.17$

The circumference of the tire should be about 2.17 feet.

5 0

3 years ago

Which system of linear equations has no solution?

Nesterboy [21]

Your answer is c i pretty insurance

5 0

4 years ago

You have decided to purchase a car for $22,346. 16. The credit union requires a 10% down payment and will finance the balance wi

Natali [406]

The amount that the credit union will finance is $24169.60

We have given that the cost of the car is $22,346. 16

and the credit union required 10% down payment

and sale tax=7.6%

The license and title charges are $125. 13.

We have to determine that the amount that the credit union will

finance Now we have sale tax 7.6% for $22,346. 16

Therefore, we get

$\frac{7.6}{100} \times 22,346. 16=1698.31$

<h3>What is the amount that the credit union finance ?</h3>

credit union finance=cost of car+sales tax+the license and title charges.

$=22346.16+1698.31+12.13\\=24169.60$

Therefore, the amount that the credit union will finance is $24169.60

To learn more about the credit union will finance visit:

brainly.com/question/15641576

4 0

2 years ago

At a large nursery, a border for a rectangular garden is being built. Designers want the border’s length to be twice as long as

sasho [114]

Let

x--------> the border’s length

y--------> the border’s width

P--------> perimeter of the border

we know that

x=5+y------> equation 1

P=2*[x+y]-----> P=2x+2y

P <=180 ft

(2x+2y) <= 180-------> equation 2

substitute the equation 1 in equation 2

2*[5+y]+2y <= 180

10+2y+2y <= 180

4y <= 180-10

4y <=170

y <=42.5 ft

the maximum value of the width is 42.5 ft

for y=42.5 ft

x=42.5+5------> x=47.5 ft

the answer is

the width of the border is less than or equal to 42.5 ft

7 0

3 years ago

I have a question here. ​

I have a question here.