Question

I have a question here. ​

Answer 1

Answer:

3 ways

Step-by-step explanation:

n = 3; r = 2

$nC_{r}=\dfrac{n!}{r!(n-r)!}\\\\3C_{2}=\dfrac{3!}{2!1!}=\dfrac{3*2*1}{2*1}=3$