Is a rectangle a rhombus

Mathematics

2 answers:

jek_recluse [69]4 years ago

4 0

Answer:

Yes!

Step-by-step explanation:

That’s because a square is a parallelogram with four congruent sides and four right angles.

Travka [436]4 years ago

3 0

Yes a rectangle is a rhombus

You might be interested in

-<br> 24x4 – 18x3 + 4x2 - 3x = 0<br> -<br> Solve

Snowcat [4.5K]

Answer:

x = 16.6666666667

Step-by-step explanation:

24x4 - 18x3 + 4x2 - 3x =0

24x4 = 96

18 x 3 = 54

4x2 = 8

96-54+8= 50

50/3 = 16.6666666667

7 0

3 years ago

Read 2 more answers

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$