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777dan777 [17]
3 years ago
13

a quality control officer is randomly checki g the weights of flour bags being filled by an automstic filling machine. Each bag

is advertised as weighing 500 grams. A bag must weigh within 5.3grams in order to be accepted. What is the range of rejected bags x for the bags of flour​
Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

I think the correct answer from the choices listed above is the last option. The range of the rejected bags, x, for the bags of flour. A bag of flour is said to  weigh within 3.2 grams in order to be accepted. Therefore, it should weigh within 746.8 to 753.2 grams. Outside that range is rejected.

Step-by-step explanation:

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NEED HELP ASAP PLEASE
AnnZ [28]

Answer:

8.5%

Step-by-step explanation:

I=PRT

85= 2000*r*0.5

85=1000r

0.085=r

8.5%

6 0
3 years ago
Find the solutions to 2x⁴-24x²+40=0 and the x-intercepts of the graph of y=2x⁴-24x²+40.
jekas [21]

Answer:

The solutions and the x-intercepts of the polynomial 2x^4-24x^2+40 are:

x=\sqrt{10},\:x=-\sqrt{10},\:x=\sqrt{2},\:x=-\sqrt{2}

Step-by-step explanation:

Given a function <em>f</em> a solution or a root of <em>f</em> is a value x_{0} at which f(x_0)=0.

An x-intercept is a point on the graph where y is zero.

To find the solutions of the polynomial and the x-intercepts 2x^4-24x^2+40 you need to:

First, we need to factor the polynomial expression

Factor the common term

{\left(2 x^{4} - 24 x^{2} + 40\right)} = {\left(2 \left(x^{4} - 12 x^{2} + 20\right)\right)}

We can treat x^{4} - 12 x^{2} + 20 as a quadratic function with respect to x^2

Let u=x^2. We can rewrite x^{4} - 12 x^{2} + 20 in terms of u as follows:

u^2-12u+20

We need to solve the quadratic equation

u^2-12u+20=0

for this we can use the Quadratic Equation Formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-12,\:c=20:\quad u_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}

u_1=\frac{-\left(-12\right)+\sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}\\u_1=10

u_2=\frac{-\left(-12\right)-\sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}\\u_2=2

the solutions to the quadratic equation are:

u=10,\:u=2

Therefore, u^2-12u+20=(u-10)(u-2)

Recall that u=x^2 so

2 x^{4} - 24 x^{2} + 40=2 \left(x^{2} - 10\right) \left(x^{2} - 2\right)=0

Using the Zero factor Theorem: If ab = 0, then either a = 0 or b = 0, or both a and b are 0.

x^2-10=0 roots are x_1=\sqrt{10}; x_2=-\sqrt{10}

x^{2} - 2=0 roots are x_1=\sqrt{2}; x_2=-\sqrt{2}

The solutions and the x-intercepts are:

x=\sqrt{10},\:x=-\sqrt{10},\:x=\sqrt{2},\:x=-\sqrt{2}

Because all roots are real roots the x-intercepts and the solutions are equal.

7 0
3 years ago
Find the surface area
s2008m [1.1K]

Answer:

first seperate the 2 and multiply

Step-by-step explanation:

5 0
3 years ago
Which number is the greatest -1.264,-5/4,-1.015,-0.480,-14/25,-13/8
harina [27]
These are all negative SO the number that is the greatest would be -.480. 
6 0
4 years ago
State the degree and leading coefficient of each polynomial in one variable -12-8x^2+5x-21x^7
leonid [27]

Answer:

The degree is 7 and the leading coefficient is -21.

Step-by-step explanation:

The degree of an equation is found using the highest exponent on the variable in the equation.

-12-8x^2+5x-21x^7 has the term x^7 so its degree is 7

The leading coefficient is the coefficient of the term with the highest degree. The coefficient of x^7 is -21.

4 0
3 years ago
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