2 years ago

Given f(x)= x3 and g(x) = 2x + 7, express (fºg)(x)'as a function of x.

Mathematics

1 answer:

vodomira [7]2 years ago

7 0

Answer:

(f∘g)(x)=(2x+7)^3

Step-by-step explanation:

substitute g(x) in f(x)

(f∘g)(x)=f(g(x))=f(2x+7)=(2x+7)^3=(2x+7)^3

You might be interested in

I need help please I will give brainless

Allisa [31]

Answer:

D :)

Step-by-step explanation:

6 0

3 years ago

18 divided by tan 30

Arlecino [84]

Answer:

18cot(30) or nearly -2,81016

6 0

3 years ago

A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu

Mars2501 [29]

Answer:

There can be at most $12$ attendees in a corporate team-building event.

Step-by-step explanation:

Let $x$ denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

$19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12$

So, there can be at most $12$ attendees in a corporate team-building event.

8 0

3 years ago

Twice a number is equal to fourteen

Luba_88 [7]

7 should be the answer.
7 doubled is 14. Hope this helps

3 0

3 years ago

Read 2 more answers

For a scavenger hunt, Jim's mom distributed a bag of 440 jelly beans evenly into 20 plastic containers and hid them around the y

natulia [17]

Answer: 11

Step-by-step explanation:

Given

Jim's mom distributed a bag of 440 Jelly beans evenly in to 20 Plastic bags

i.e.each bag has $\frac{440}{20}=22$ Jelly.

After the hunt, Jim has 242 Jelly. This much Jelly constitutes

$\Rightarrow \dfrac{242}{22}=11\ \text{bags}$

Therefore, Jim has 11 bags of Jellys

6 0

3 years ago