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elixir [45]
3 years ago
14

Given f(x)= x3 and g(x) = 2x + 7, express (fºg)(x)'as a function of x.

Mathematics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

(f∘g)(x)=(2x+7)^3

Step-by-step explanation:

substitute g(x) in f(x)

(f∘g)(x)=f(g(x))=f(2x+7)=(2x+7)^3=(2x+7)^3

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Solve using substitution. -2x - 2y = -14 <br>3x + 4y = 19​
hoa [83]

Answer:

69

Step-by-step explanation:

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3 0
3 years ago
If the numerator of a fraction is increased by six, the value of the fraction will increase by one. If the denominator of the or
Alchen [17]

Answer:

\dfrac{7}{6}

Step-by-step explanation:

Let \dfrac{a}{b} be the original fraction.

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. Hence,

\dfrac{a+6}{b}=\dfrac{a}{b}+1

If the denominator of the original fraction is increased by 36, the value of the original fraction will decrease by one. Hence,

\dfrac{a}{b+36}=\dfrac{a}{b}-1

Add these two equalities:

\dfrac{a+6}{b}+\dfrac{a}{b+36}=\dfrac{a}{b}+1+\dfrac{a}{b}-1\\ \\\dfrac{a+6}{b}+\dfrac{a}{b+36}=2\dfrac{a}{b}\\ \\\dfrac{a}{b+36}=\dfrac{2a-(a+6)}{b}\\ \\\dfrac{a}{b+36}=\dfrac{a-6}{b}\\ \\ab=(a-6)(b+36)\\ \\ab=ab+36a-6b-216\\ \\36a-6b-216=0\\ \\6a-b-36=0\\ \\b=6a-36

Substitute it into the first equation:

\dfrac{a+6}{6a-36}=\dfrac{a}{6a-36}+1\\ \\\dfrac{a+6}{6(a-6)}=\dfrac{a}{6(a-6)}+1\\ \\a+6=a+6(a-6)\\ \\a+6=a+6a-36\\ \\6a=6+36\\ \\6a=42\\ \\a=7\\ \\b=6\cdot 7-36=42-36=6

Thus, the initial fraction was

\dfrac{7}{6}

6 0
4 years ago
If ∪≈[1,2,3,4,5}and A≈{1,2,3}them find A
myrzilka [38]

Answer:

[4,5]

Step-by-step explanation:

A = U-A

= [1,2,3,4,5]-[1,2,3]

= [4,5]

Mark me brainlist .

7 0
3 years ago
Sarah has two similar regular pyramids with pentagon-shaped bases. The smaller has a scale factor of 2:3 when compared to the la
nordsb [41]

Answer:

(a) The volume of the pyramid 440.44 cube units

(b) No she doesn't

(c) The volume of the larger pyramid is 1,486.485 cube units

Step-by-step explanation:

The given parameters are;

The scale factor of the pyramids, S.F. = 2:3

The base area of the small pyramid, A_{b1} = 110.11 square units

The height of the small pyramid, h₁ = 12 units

(a) The volume of a pyramid, V = (1/3) × Area of base × The height of the pyramid

Therefore;

The volume of the small pyramid, V₁ = (1/3) × 110.11 square units × 12 units

V₁ = 440.44 cube units

The volume of the small pyramid, V₁ = 440.44 cube units

(b) No she does not have to go through all the hard work again to find the volume of the larger pyramid

She only has to make use of the scale factor relationships of the two pyramid to calculate the volume of the larger pyramid

The volume scale factor = (The linear scale factor)³

(c) The linear scale factor of the pyramids = 2:3 = 2/3

Therefore;

The volume scale factor of the pyramids = (2/3)³ = 8/27

To find the volume of the larger pyramid, V₂, from the volume of the smaller pyramid, V₁, we multiply the volume of the smaller pyramid, V₁,  by 27/8 as follows;

V₂ = V₁ × (27/8)

Therefore;

The volume of the larger pyramid, V₂ = 440.44 cube units × (27/8) = 1,486.485 cube units

The volume of the larger pyramid, V₂ = 1,486.485 cube units.

5 0
3 years ago
X is greater than or equal to -7
Amanda [17]

Answer:

x ≥ -7

Step-by-step explanation:

greater than or equal to ≥

x ≥ -7

5 0
3 years ago
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