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joja [24]
4 years ago
15

Which is the solution to the inequality?

Mathematics
2 answers:
Tanzania [10]4 years ago
8 0

Answer:

y < -12

Step-by-step explanation:

Subtract 12 from both sides:

y + 15 - 15 < 3 - 15

Simplify:

y < -12

lord [1]4 years ago
6 0
I think the answer is y<-12 :))
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Solve for x.<br><br> 7 x = 4 x + 27<br><br> x =
rosijanka [135]

Answer:

x=9

Step-by-step explanation:

7x = 4x + 27

subtract 4x on both sides

3x=27

divide 3 on both sides

x=9

plug in

7(9)=63

4(9)+27=63

63=63

6 0
3 years ago
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Y = 2x + 1<br> y = -2x + 1<br> y = -2x - 0.5<br> y = 2x - 0.5
Eddi Din [679]

have you seen how he answers questions? doesn't deserve to have people answer his

Step-by-step explanation:

7 0
3 years ago
PLS HELP THANK UUU!!!
Svetach [21]

Answer:

47.45754235

31.46697634

Hey do you need to show your work for these? I found an answer key

Step-by-step explanation:

We need to use law of cosines

c²=a²+b²-2abcos(C)

let x= angle xzy

plugging in what we have the equation looks like

17²=22²+20²-2*22*20*cos(x)

289=484+400-880cos(x)

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x=47.45754235

b.)

The smallest angle should be opposite to the smallest side

Using the law of cosines again we get

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6 0
3 years ago
The sum of three consecutive integers is 36. Find the largest integer.
cestrela7 [59]

Answer:

13

Step-by-step explanation:

(n-2) +(n-1) +n =3n-3=36

n=(36+3)/3=13

Consecutive integers are 11,12 and 13

5 0
4 years ago
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Prove that the number A= [tex]20^{8^{2014} } }+113 is composite
Drupady [299]

Cheese proof:

We can just prove that it is divisible by 3, which means that it is composite. We can use modular exponentiation, where if a \equiv b \pmod{n} then a^x \equiv b^x \pmod{n}. In this case, {-1}^{8^{2014}} \equiv 20^{8^{2014}} \pmod{3}. This is much easier to calculate! Since 8^{2014} is even, -1^{8^{2014}}=1, meaning that now we only need to prove that 0\equiv(1+113) \pmod{3}, which is obviously true.

8 0
2 years ago
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