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dexar [7]
3 years ago
11

PLS HELP THANK UUU!!!

Mathematics
1 answer:
Svetach [21]3 years ago
6 0

Answer:

47.45754235

31.46697634

Hey do you need to show your work for these? I found an answer key

Step-by-step explanation:

We need to use law of cosines

c²=a²+b²-2abcos(C)

let x= angle xzy

plugging in what we have the equation looks like

17²=22²+20²-2*22*20*cos(x)

289=484+400-880cos(x)

.676136364=cos(x)

x=47.45754235

b.)

The smallest angle should be opposite to the smallest side

Using the law of cosines again we get

9²=13²+17²-2*13*17*cos(x)

81=458-442cos(x)

.852941176=cos(x)

x=31.46697634

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Step-by-step explanation:

if Amid needs 32.9 m for one tent  he will need

32.9 x 12= 394.8 m for 12 tents

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2 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

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