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aleksley [76]
3 years ago
15

Pleaseee help me solve this question

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

y=3x

Step-by-step explanation:

You might be interested in
Surface area???????????
MAVERICK [17]

Answer:

The option B is the correct answer. 79.18 m²

Step-by-step explanation:

Surface area = Base area +  Lateral surface area

Area of triangle = bh/2

b - base and h - height

<u>To find the base area</u>

We can consider the base is a hexagon.

A regular hexagon is a combination of 6 equilateral  triangle

Base area = 6 * area of triangle

base b = 3

<u>To find the height</u>

h =√[(6.2)² - (5.6)₂] = 2.7

Area of triangle bh/2 = (3 * 2.7)/2 = 3.99

Area of base = 23.95

To find lateral surface area

Lateral surface area = 6 * area of triangle

Area of triangle = bh/2 =(3 *6.2)/2 = 9.3

Lateral surface area = 6 * 9.3 = 55.8

<u>To find the total surface area </u>

Total surface area = Base area + lateral surface area = 23.95 + 55.8

= 79.75 m²

Therefore the option B is the correct answer. 79.18 m²

7 0
3 years ago
Which inequality is graphed below
Aneli [31]

Answer:

C.

Step-by-step explanation:

> is a dotted line and the area above it is shaded

< is a dotted line and the area below it is shades

≥  is solid line with the area above shaded

≤ is a solid line with the area below it shaded

The graph shows characteristics of ≥, and C is the only answer with ≥ in it

6 0
3 years ago
Help please&lt;3
ale4655 [162]
Y=-3/2x+4

The slope is -3/2, since Kerry traveled three feet and only went down 2.

The y intercept is 4, since she started four feet above the origin
3 0
3 years ago
HELP ⚠️⚠️⚠️⚠️⚠️⚠️⚠️ HELP<br> Please and thank you!
Reika [66]

Answer:

can't see the pic

Step-by-step explanation:

8 0
3 years ago
Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).
Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>
  • The critical points of a function are the values of x for which:

f^{\prime}(x) = 0

In this problem, the function is:

f(x) = x^3 + ax^2 + b

Hence, the derivative is:

f^{\prime}(x) = 3x^2 + 2ax

Then:

f^{\prime}(x) = 0

3x^2 + 2ax = 0

x(3x + 2a) = 0

x = 0

3x + 2a = 0

3x = -2a

x = -\frac{2a}{3}

Since the critical point is at x = 2, we have that:

-\frac{2a}{3} = 2

-2a = 6

2a = -6

a = -3

Then:

f(x) = x^3 - 3x^2 + b

Critical point at (2,3) means that when x = 2, y = 3, then:

3 = 2^3 - 3(2)^2 + b

8 - 12 + b = 3

b = 7

You can learn more about the critical point concept at brainly.com/question/2256078

4 0
1 year ago
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