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3 years ago

Which of these triangels apears not to be congruent to any others shown here check all that apply

Mathematics

2 answers:

masha68 [24]3 years ago

6 0

Triangles are congruent when they have exactly the same three sides and exactly the same three angles.

The diagram shows two pairs of congruent triangle:

triangle C is congruent to triangle E (have exactly the same three sides and exactly the same three angles);
triangle D is congruent tot triangle F (have exactly the same three sides and exactly the same three angles).

Triangles A and B apears not to be congruent to any others triangles.

Naily [24]3 years ago

4 0

To me, only triangle b looks like it is not congruent to any other.

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Find the length of the third side to the nearest tenth. 3 7

kogti [31]

Answer:

uhm 5?

Step-by-step explanation:

because 3 we move 1 more is 4.

and 7 we go -1 which is 6 so we have 5 in the middle so the answer is 5!

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3 years ago

What type of angles are <5 and <16

vovikov84 [41]

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3 years ago

Is ABC=XYZ? PLEASE HELP!!

statuscvo [17]

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3 years ago

A new mixture of self-tanning & moisturizing lotions for everyday use is being developed. This mixture is made by mixing 70

777dan777 [17]

Answer:

450 ounces

Step-by-step explanation:

We know that the cost of the mixture $C_m$ must be the cost of the everyday moisturizing lotion $C_e$ plus the cost of the self-tanning lotion $C_s$ , which means $C_m=C_e+C_s$ .

The cost of any substance will be the cost per ounce of the substance (c), multiplied by the number of ounces (n), which means C=nc, so we have from the previous formula that we have:

$n_m c_m=n_e c_e + n_s c_s$

But we also know that the number of ounces of the mixture must be the sum of the number of ounces of the everyday moisturizing lotion with the number of ounces of the self-tanning lotion, so we have

$n_e c_e + n_s c_s=n_m c_m=(n_e+n_s) c_m=n_e c_m+n_s c_m$

We want to calculate the number of ounces of the self-tanning lotion ( $n_s$ ), so we solve for that variable:

$n_e c_e + n_s c_s=n_e c_m+n_s c_m$

$n_s c_s-n_s c_m=n_e c_m-n_e c_e$

$n_s (c_s-c_m)=n_e(c_m-c_e)$

$n_s=\frac{n_e (c_m-c_e)}{(c_s-c_m)}$

And substitute our values in this formula, to get:

$n_s=\frac{(700\ ounces) (\$1.6-\$0.7)}{(\$3-\$1.6)}=450\ ounces$

7 0

4 years ago

The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.

Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

Step-by-step explanation:

Let X denote the heights of women in the USA.

It is provided that X follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

$P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z$

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z$

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

$P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0$

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0

3 years ago