Answer: There are 1800 unique names from both the lists.
Explanation:
Since we have given that
there are two lists :
In First list, number of names = 1200
In Second list, number of names = 900
According to question , we have also given that
there are 150 names that appear on both lists,
So,
Number of unique names in the first list is given by
Number of unique names in the second list is given by
Therefore, total number of unique names is given by
Hence, there are 1800 unique names from both the lists.
Answer:
363
Step-by-step explanation:
Formula for area of a circle
A = πr^2
Where r = radius
The circle has a given radius of 11
To find the area of the circle we simply substitute r in the formula with the value of the radius (11)
( Also note that the question says to use 3 for π )
A = πr^2
π = 3
r = 11
Substitute values in formula
A = (3)(11)^2
11^2 = 121
A = 121(3)
121(3) = 363
A = 363
<h3><u>Answer</u> :- </h3>
c) 0.01
<h3><u>Solution</u> :-</h3>
To Write percentage in decimal or fraction we divide it by 100
therefore,
Half of 0.02 = 
I believe that is 275 because percent is just out of one hundred
Step-by-step explanation:
I am not fully sure what your teacher is aiming for. it friends very much on what you were just discussing in class (which I don't know).
but the first thing coming to mind is a minus sign ("-"). squaring a negative number removed the minus and makes the result equal to squaring the same positive number.
just for the undoing the 1/2 :
that is, because a fraction as exponent specifies in its denominator the root to be calculated for the basic value or expression.
so, 1/2 means square root. and yes, square is the inverse function of a square root, and it "undoes" the square root.
in exponent calculation it just means that for exponent 1 to the power of exponent 2 we simply multiply both exponents. and so, 1/2 × 2 = 1
FYI - the numerator still represents an original "to the power of" operation.
so, e.g. 3/2 would mean put the basis to the power of 3 and then do the square root of that result. or the other way around. these operations are commutative (the sequence does not matter).
