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Salsk061 [2.6K]

2 years ago

15

A class is raising funds to go ice skating at the rink at campus martius in detroit.The class plans to rent one bus. It costs $1

50.00 to rent a school bus for the day, plus $11.00 per student for admission to the rink, including skates.

1 answer:

laiz [17]2 years ago

7 0

The function of this situation is y=11x+150.

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Let f(x)=x2−2x−4 . What is the average rate of change for the quadratic function from x=−1 to x = 4?

goblinko [34]

Answer:

The average rate of change for f(x) from x=−1 to x = 4 is, 1

Step-by-step explanation:

Average rate A(x) of change for a function f(x) over [a, b] is given by:

$A(x) = \frac{f(b)-f(a)}{b-a}$

As per the statement:

$f(x) = x^2-2x-4$

we have to find the average rate of change from x = -1 to x = 4

At x = -1

$f(-1) = (-1)^2-2(-1)-4 = 1+2-4 = -1$

and

at x = 4

$f(4) = (4)^2-2(4)-4 = 16-8-4 = 4$

Substitute these in [1] we have;

$A(x) = \frac{f(4)-f(-1)}{4-(-1)}$

⇒ $A(x) = \frac{4-(-1)}{4+1}$

⇒ $A(x) = \frac{5}{5}$

Simplify:

A(x) = 1

Therefore, the average rate of change for f(x) from x=−1 to x = 4 is, 1

4 0

2 years ago

Read 2 more answers

Travis and his three friends ate out at Applebee's. Their bill totaled $72.50. If they left the server a 22%

Vlad [161]

The answer is a tip =15.95

8 0

2 years ago

HELP MEE :)) PLEASEEE <3

Mandarinka [93]

<h3>Volume of the cylinder:</h3>

$v = \pi {r}^{2} h$

$v = 3.14 \times {2}^{2} \times 3$

$v = 37.68 \: {cm}^{3}$

<h3>Volume of the rectangular prism:</h3>

$v = lwh$

$v = 6 \times 5 \times 7$

$v = 210 \: {cm}^{3}$

<h3>Total volume:</h3>

$v = 37.68 + 210$

$v = 247.68 \: {cm}^{3}$

4 0

1 year ago

Read 2 more answers

Aaron run 6 miles each day for three days. How many miles does she run it all? Write an addition and a multiplication sentence t

artcher [175]

6*3=18 miles in total

8 0

2 years ago

Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent

Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly among the given student the probability that this student is wearing a ring or necklace is

$P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1$

$P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4$

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

7 0

2 years ago