Answer:
We need a sample size of at least 170.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population(square root of the variance) and n is the size of the sample.
How large of a sample would be required in order to estimate the mean per capita income at the 80%80% level of confidence with an error of at most $0.52$ 0.52?
A sample size of at least n, in which n is found when 
So
Rounding up
We need a sample size of at least 170.
THe answer will be <span>97.44%
hoped this helped</span>
Answer:
7
Step-by-step explanation:
9 - 3 * 2 + 4
9-6+4
3+4
7
Answer:
Ghww wt
Step-by-step explanation:
6h8d dgs gc
Let C = cost to rent each chairLet T = cost to rent each table
4C + 8T = 73
2C + 3T = 28
Multiply the 2nd equation by (-2) and then add the equations together
4C + 8T = 73
-4C - 6T = -56
2T = 17T = 17/2 = 8.5
Plug this in to the 1st equation to solve for C
4C + 8(17/2) = 73
4C + 68 = 73
4C = 5C = 5/4 = 1.25
So the cost to rent each chair is $1.25 and the cost to rent each table is $8.50
