Answer:
1.10
2.49z^4
Step-by-step explanation:
1.What I did was change 1/2 to a decimal and then go from there::0.5(8)-(-4)+2 ::0.5(8)=4-(-4)=8 because of KCC then 8+2=10
2.The power of a product is equal to the product of it's factors raised to the same power
I guess so, no wait no it’s not jk lol
There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.
The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758
We can make several two 3-digit numbers from these blocks. An example is listed below:
Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:
1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434
The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.
This way changing the number of blocks in each place value, different 3 digit numbers can be generated.
Answer:
3x^5y^6 (a)
Step-by-step explanation:
La raiz de un productor es igual al producto de las raices de cada factor
^4√81 ^4√x^20 ^4√y^24
escriba el numero en forma exponencial an base 3
^4√3^4 ^4√x^20 ^4√y^24
simplifica el indice de la raiz y el exponente usando 4
^4√3^4 x^5 ^4√y^24
simplifica el indice de la raiz y el exponente usando 4
^4√3^4 x^5 y^6
simplifica el indice de la raiz y el exponente usando 4
3x^5y^6
