The space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.
<h3>What is a cone?</h3>
It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.
We know the volume of the cylinder is given:
r = 10/2 = 5 FT
h = 12 FT
V = 300π cubic FT
Volume of the cone:
v = 100π cubic FT
Space is inside the cylinder but outside the cone = 300π - 100π
= 200π cubic FT
= 628.32 cubic FT
Thus, the space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.
Learn more about the cone here:
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Answer:
hmmm...? im gonna guess 2
Step-by-step explanation:
i finger plus another finger gives me......ahhhhh ik the answer its 2
Let x be the expected number
Number arriving = 3•5 x
Unexpected number 2•5 x
2•5 x = 105
10x = 420
x = 42______Option D
Answer:
Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.
Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity
Step-by-step explanation:
Given that the vector b = (-2, -1) can be written as follows;
b = -2·i - j, we have;
= √((-2)² + (-1)²) = √5
Therefore, we have;
The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)
Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2
The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))
Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.
