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4 years ago

Please help, it’s due today :)

Mathematics

2 answers:

Cloud [144]4 years ago

6 0

Answer:

x =5

Step-by-step explanation:

We can use ratios for the side lengths

9 x

--------- = -----------

9+18 x+10

Using cross products

9 (x+10) = x * (9+18)

Distribute

9x+90 = x*27

9x+90 = 27x

Subtract 9x from each side

9x-9x+90 = 27x-9x

90 = 18x

Divide each side by 18

90/18 = 18x/18

5 =x

tia_tia [17]4 years ago

3 0

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Iteru [2.4K]

answer:

x = 0.80

y = 1.50

step-by-step explanation:

x = cost of tacos

y = cost of burritos

both equations:

3x + 2y = 5.40

2x + 1y = 3.10

turn this | into this |

y = 3.10 - 2x

then add it to the equation :

3x + 2 [ 3.10 - 2x ] = 5.40

3x + 6.2 - 4x = 5.40

-1x = - 0.8

x= 0.80

then add x = 0.80 to the equations to get :

3 [ 0.80 ] + 2y = 5.40

2.4 + 2y = 5.40

2y = 3

y = 1.5

5 0

3 years ago

Please help me I will give a brainlist

soldier1979 [14.2K]

Answer:

I think this is helpful .

3 0

3 years ago

How many different strings of length 12 containing exactly five a's can be chosen over the following alphabets? (a) The alphabet

N76 [4]

Answer:

Part (A) The required ways are 792.

Part (B) The required ways are 101376.

Step-by-step explanation:

Consider the provided information.

Part (A) The alphabet {a, b}

The length of strings is 12 that containing exactly five a's.

The number of ways are: $\frac{12!}{5!7!}$

After filling "a" we have now 7 places.

For 7 places we have "a" and "b" alphabet but we already select a's so now the remaining place have to fill by "b" only.

Thus, the required ways are: $\frac{12!}{5!7!}\times 1=792$

Part (B) The alphabet {a, b, c}

We have selected five a's now we have now 7 places.

For 7 places we have "b" and "c".

Thus, there are 2 choices for each 7 place that is $2^7$

Therefore the total number of ways are: $792\times 2^7=101376$

Thus, the required ways are 101376.

7 0

4 years ago

Which of the following are identities?

frosja888 [35]

Answer:

A and D.

Step-by-step explanation:

(sin(x-y))/(cosxcosy)

(sinxcosy - cosxsiny) / cosxcosy

= sinx / cosx - siny/cosy

= tanx - tany.

So A is an identity.

B. (sin(x+y))/(sinxsiny)

= sinx cosy + cosx siny / sinxsiny

= cosy/siny + cosx/sinx

= 1/tany + 1/tanx which is not identical with 1-tanxtany.

C. tan ( x - pi/4) = ( tan x - 1) / (1 + tanx) : - not identical to tanx - 1.

D. cos( x + (pi/6) = cosxcos(pi/6) - sinxsin(pi/6)

= 0.866cosx - 0.5sinx

- sin(x - (pi/3) = -(sinxcos(pi/3) - cosxsin(p/3))

= - (0.5sinx - 0.866cosx0

= 0.866cos x - 0.5sinx.

which are identical.

4 0

3 years ago

If f(x) = 6x-4, what is f(x) when x = 8

NARA [144]

Answer:

The correct answer is 44

Step-by-step explanation:

6(8)-4

48-4

5 0

4 years ago

Read 2 more answers