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RideAnS [48]
3 years ago
7

Kennedy lives in the middle of the city. Her friend Zoe lives 8 miles to the west and her friend Shiloh lives 6 miles to the sou

th. Approximately how far apart do Zoe and Shiloh live from each other?
Mathematics
2 answers:
Kamila [148]3 years ago
5 0

Answer:

i would say about 16 miles.

Katarina [22]3 years ago
4 0

Answer:

Step-by-step explanation:

Draw a picture. The lines between their houses forms a right triangle. Kennedy is at the 90°. The distance between Shiloh and Zoe is the hypotenuse of the triangle, so use the Pythagorean Theorem.

Distance² = 8² + 6² = 100

Distance = √100 = 10 miles

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Step-by-step explanation:

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3 years ago
HELP NEEDED ASAP WILL GIVE 5 STAR RATING AND BRAINLIEST!
stealth61 [152]

Answer:

The answer to your question is: ∠K   = 138°

Step-by-step explanation:

m∠N = 42°

m∠K = ?

The sum of all the internal angles in a quadrangle equals 360°

then

        ∠N + ∠L + ∠M + ∠K = 360°

        ∠N = ∠ L   and ∠M = ∠K

So, 2 ∠N + 2 ∠K = 360

Substitution

       2 (42) + 2 ∠K = 360

       84  + 2 ∠K = 360

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8 0
2 years ago
Twelve is added to the product of a number and 5. The result is -3. Find the number. And write an equation for this. SHOW FULL W
Free_Kalibri [48]

Let the number be x


Equation:

12 + 5x = -3


Answer: The equation is 12 + 5x = -3


Solve it:

5x = -3 - 12

5x = -15

x = -15 ÷ 5

x = -3


Answer: The number is -3.


3 0
3 years ago
Read 2 more answers
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

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2 years ago
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