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vampirchik [111]
3 years ago
7

Four times the sum of a number and eight times the number is 252. Find number

Mathematics
1 answer:
Tom [10]3 years ago
8 0
The answer is 27 2+7=9x4=36 27x4=216  
216+36=252
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What is the decimal equivalent of 9 over 12
Marrrta [24]

Answer:

0.75

Step-by-step explanation:

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3 years ago
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A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
kotegsom [21]

Answer: 68

Step-by-step explanation:

Formula for sample size when prior estimate of population proportion (p) is available:  n=p(1-p)(\dfrac{z^*}{E})^2

, where z*= critical-value.

E= Margin of error.

Let p be the population proportion of  trees are infected with the citrus red mite.

As per given , we have

p=\dfrac{1}{5}=0.2

E= ± 0.08

The critical z-value corresponding to 90% confidence level = z*=1.645

Substitute all the values in the above formula , we get

Required sample size  :n=(0.2)(1-0.2)(\dfrac{(1.645)}{0.08})^2

\Rightarrow\ n=(0.2)(0.8)(20.5625)^2

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6 0
3 years ago
Find the slope of f(x)=5x-4
frosja888 [35]

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Step-by-step explanation:

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Write the fraction in terms 45/75
NARA [144]
The Answer is 3/5
<span>
The gcd of 45 and 75 is 15, so 45/75 = (15×3)/(15×5) = 15/15×3/5 = 3/5:

Answer:  3/5</span>
4 0
3 years ago
The table shows the American League batting champions for the years 1999–2003. The sum of these five batting averages is 1.754.
fgiga [73]
The answer is <span>A. .357 + .372 + .350 + .349 + x = 1.754; .326 
</span>
x1 - average of <span>1999 Nomar Garciaparra Boston
</span>x2 - average of 2000 Nomar Garciaparra Boston
x3 - average of <span>2001 Ichiro Suzuki Seattle 
</span>x4 - average of Manny Ramirez Boston  
x - average of <span>2003 Bill Mueller Boston 

</span><span>The sum of these five batting averages is 1.754:
x1 + x2 + x3 + x4 + x = 1.754

From the table:
x1 = 0.357
x2 = 0.372
x3 = 0.350
x4 = 0.349
x = ?

<u>0.357 + 0.372 + 0.350 + 0.349 + x = 1.754</u>

1.428 + x = 1.754
x = 1.754 - 1.428
<u>x = 0.326</u></span>
5 0
3 years ago
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