A family gathered 20 small sea shells from the beach brining the total number of small seashells in their collection to 41.

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

5 0

Answer:

C, x + 20 = 41

Step-by-step explanation:

X represents the number of small sea shells that we originally had. When the family adds 20 more shells, that makes x + 20. The total number is 41, so that means the number of sea shells they already had (x) plus the number of sea shells they collected (20) equals the number of shells they have now (41).

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The number of pollinated flowers as a function of time in days can be represented by the function. f(x)

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The average increase in the number of flowers pollinated per day between days 4 and 10 is <u>39</u>, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

In the question, we are asked for the average increase in the number of flowers pollinated per day between days 4 and 10, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

To find the average increase in the number of flowers pollinated per day between days 4 and 10, we use the formula {f(10) - f(4)}/{10 - 4}.

First, we find the value of the function $f(x) = (3)^{\frac{x}{2} }$ , for f(10) and f(4).

$f(x) = (3)^{\frac{x}{2} }\\\Rightarrow f(10) = (3)^{\frac{10}{2} }\\\Rightarrow f(10) = 3^5 = 243$

$f(x) = (3)^{\frac{x}{2} }\\\Rightarrow f(4) = (3)^{\frac{4}{2} }\\\Rightarrow f(10) = 3^2 = 9$

Thus, the average increase

= {f(10) - f(4)}/{10 - 4},

= (243 - 9)/(10 - 4),

= 234/6

= 39.

Thus, the average increase in the number of flowers pollinated per day between days 4 and 10 is <u>39</u>, given that the number of pollinated flowers as a function of time in days can be represented by the function $f(x) = (3)^{\frac{x}{2} }$ .

Learn more about the average increase in a function at

brainly.com/question/7590517

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