The Diameter of the circle =7m
Answer:
1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means
Example;
y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3
2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations
2x + 6y = 16
x + y = 6
We can substitute the value of x = 6 - y, into the first equation and solve from there
3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16
Multiplying the second equation by 2 and subtracting it from the first equation as follows
2·x + 6·y - 2×(x + y) = 23 - 2 × 16
2·x - 2·x + 6·y - 2·y = 23 - 32
0 + 4·y = -9
4) An example of a linear system that can be solved by all three methods is given as follows;
2·x + 6·y = 23
x + y = 16
Step-by-step explanation:
William has $240 to Michael's $420
this can be written in a ratio as 240 : 420
which can then be reduced to
24:42
12:21
4:7
Step-by-step explanation:
D= 56t
D= 60t -2
D= Distance T=time d = 56t (Jordan) d = 60t - 2 (Roman)
d = 56t d = 60t - 2
56t = 60t - 2 d = 56(1/2) d = 60(1/2) - 2
-60t -60t d = 28 d = 30 - 2 = 28
-4t = -2
t = 1 / 2
Answer: 0 x 3
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