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3 years ago

A Turtle traveled 1/10 mile in 1/2 hour. What was the turtle’s rate in miles per hour?

Mathematics

1 answer:

AnnZ [28]3 years ago

6 0

1/5

1/10 / 1/2= 2/10
Then simplify it by 2, it becomes D.1/5

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Solve for x.. 3(x-8) = 29.7

mr Goodwill [35]

Answer:

x = 17.9

Step-by-step explanation:

$3x-24=29.7\\ Distribution Property\\\\3x=53.7\\\\Adding 24 to both sides\\\\x=17.9\\Divide by 3 to both sides\\\\Hope this helps:)\\$

6 0

3 years ago

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Consider the function f(x)= x² - 4

Arisa [49]

Answer:

(X+2) (X-2) . This is the final answer

Step-by-step explanation:

Solving f(x) = x^2 - 4

A^2 - B^2 is a special case where the original equation before it was foiled is

(A + B) (A - B) because the middle terms will cancel out when foiled.

This means that the equation can be written as

(X + 2)(X - 2) = 0

Each of these you will then set equal to 0 and then solve

X + 2 = 0, X - 2 = 0

X = -2, 2

I hope this helps you! let me now if its right ok <3 :)

4 0

3 years ago

Which statement comparing these measures is true? A microgram is 1,000 times greater than a milligram.

ololo11 [35]

The statement is false.

The statement below is true.
A milligram is 1000 times greater than a microgram.

3 0

3 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago

Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B2 to both sides of the equation in step 4,

Katena32 [7]

2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10

x = -2 + sqrt 10
x = -2 - sqrt 10

3 0

3 years ago

Read 2 more answers